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notsponge [240]
3 years ago
6

Lesson 9: When Are They the Same?

Mathematics
1 answer:
marysya [2.9K]3 years ago
8 0

Answer:

The number of pages that will make the cost of printing equal for both options is 500

Step-by-step explanation:

Please, kindly see the attached file for explanation

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Help me please asap due tomorrow​
slava [35]

Answer: 87.5

Step-by-step explanation:

Triangle area = base * height / 2

25 * 7 = 175

175/ 2 = 87.5

4 0
3 years ago
How do you do this? Please help!
jeka94
A=((8.9+8.9)/2) * 5.4 = 48.06P= 8.9*2 +6*2 = 28.4
4 0
2 years ago
HELP I WILL GIVE BRAINLIEST
Shalnov [3]

Answer: a

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
A hyperbola centered at the origin has verticies at (add or subtract square root of 61,0 and foci at (add or subtract square roo
deff fn [24]

Answer:

\frac{x^2}{61}-\frac{y^2}{37}  =1

Step-by-step explanation:

The standard equation of a hyperbola is given by:

\frac{(x-h)^2}{a^2} -\frac{(y-k)^2}{b^2} =1

where (h, k) is the center, the vertex is at (h ± a, k), the foci is at (h ± c, k) and c² = a² + b²

Since the hyperbola is centered at the origin, hence (h, k) = (0, 0)

The vertices is (h ± a, k) = (±√61, 0). Therefore a = √61

The foci is (h ± c, k) = (±√98, 0). Therefore c = √98

Hence:

c² = a² + b²

(√98)² = (√61)² + b²

98 = 61 + b²

b² = 37

b = √37

Hence the equation of the hyperbola is:

\frac{x^2}{61}-\frac{y^2}{37}  =1

6 0
3 years ago
Three charges are arranged in an equilateral triangle with sides of 4 cm. The coordinates and corresponding charge values are as
lisov135 [29]
To determine the answer of Part A draw the equilateral triangle and the to determine the coordinates of of the third charge use that triangle.
To calculate the gravitational field strength in part B from each of the charges use the following equation.

E=kcq/r2

If you would add those values then you can use the symmetry about the y axis to make the vector addition a litter easier.<span />
6 0
3 years ago
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