solution:
Z1 = 5(cos25˚+isin25˚)
Z2 = 2(cos80˚+isin80˚)
Z1.Z2 = 5(cos25˚+isin25˚). 2(cos80˚+isin80˚)
Z1.Z2 = 10{(cos25˚cos80˚ + isin25˚cos80˚+i^2sin25˚sin80˚) }
Z1.Z2 =10{(cos25˚cos80˚- sin25˚sin80˚+ i(cos25˚sin80˚+sin25˚cos80˚))}
(i^2 = -1)
Cos(A+B) = cosAcosB – sinAsinB
Sin(A+B) = sinAcosB + cosAsinB
Z1.Z2 = 10(cos(25˚+80˚) +isin(25˚+80˚)
Z1.Z2 = 10(cos105˚+ isin105˚)
210 pieces
Step-by-step explanation:
First, you need to figure out how many pieces a single machine can cut in a minute, so you need to divide 105 by 3, which gets you 35 pieces per minute.
Next, since we know there are 6 machines, and one machine canncut 35 pieces per minute, we can the figure out how many pieces all 6 cutting machines can cut in 1 minute. You would do this by making an equation such as this:
The x represents the total number of pieces cut by all 6 machines in one minute.
Next, since we now have an equation, we can go ahead and solve it. We would multiply 35 by 6, which would get us 210 pieces per minute that can be cut by all six machines
The question we need to ask is what percent of 2 is 40?
40 is 20 times 2 so 20 would be 2,000%
We need to subract 100% from any percent change:
2,000% - 100% = 1,900%
ANSWER: 1,900%
Answer:
a
Step-by-step explanation:
Answer:
65°
Step-by-step explanation:
JM = JK (all sides of a rhombus are equal)
Angle JKM = 25° (isosceles triangle)
Angle JKL = 50° (consecutive angles of rhombus)
Angle MKL = 25° (angle subtraction)
Angle MLK = 130° (opposite angles of a rhombus)
Angle KLN = 50° (angles on a straight line)
Angle LKN = 40° (angle sum of triangle)
Angle MKN = 65° (angle addition)
