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ikadub [295]
4 years ago
13

Find the product of the complex numbers. Express your answer in trigonometric form. z1 = 5(cos(25) + isin(25)) z2 = 2(cos(80) +

isin(80))
Mathematics
1 answer:
zmey [24]4 years ago
5 0

solution:

Z1 = 5(cos25˚+isin25˚)

Z2  = 2(cos80˚+isin80˚)

Z1.Z2  = 5(cos25˚+isin25˚). 2(cos80˚+isin80˚)

Z1.Z2  = 10{(cos25˚cos80˚ + isin25˚cos80˚+i^2sin25˚sin80˚) }

Z1.Z2  =10{(cos25˚cos80˚- sin25˚sin80˚+ i(cos25˚sin80˚+sin25˚cos80˚))}

(i^2 = -1)

Cos(A+B) = cosAcosB – sinAsinB

Sin(A+B) = sinAcosB + cosAsinB

Z1.Z2 = 10(cos(25˚+80˚) +isin(25˚+80˚)

 Z1.Z2     = 10(cos105˚+ isin105˚)


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Answer:

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2 years ago
Points J and K are midpoints of the sides of triangle FGH. Triangle F G H is cut by lines segment J K. Point J is the midpoint o
anastassius [24]

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Value of y = 7

Step-by-step explanation:

By the midpoint theorem of the triangles,

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Therefore, from the figure attached,

In ΔFGH,

J and K are the mid points of the two sides GH and FH.

By theorem, segment JK║GF and m(JK) = \frac{1}{2}m(FG)

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5y + 3 = 4y + 10

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7 0
3 years ago
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Melissa worked to earn $20.00. Alan worked for $12.00 hours. If she earns $2.00 per hour, how many hours did Melissa work?
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4 years ago
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BabaBlast [244]

Answer:

the answer would be d

Step-by-step explanation:

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Answer:

Graph C with the green dots.

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