Question

The coordinates of quadrilateral FGHJ are F(-5, -3), G(-3, 3), H(3, 5), and J(7, -1). Find the midpoint of line HJ

Answer 1

(5,2) - midpoint ...

Answer 2

Answer:

(5,2)

Step-by-step explanation:

It is given that The coordinates of quadrilateral FGHJ are F(-5, -3), G(-3, 3), H(3, 5), and J(7, -1).

Now, the mid point is given as:

$M=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

Then, the mid point of HJ having coordinates  H(3, 5), and J(7, -1)is:

$M=(\frac{3+7}{2},\frac{5+(-1)}{2})$

$M=(\frac{3+7}{2},\frac{5-1}{2})$

$M=(\frac{10}{2},\frac{4}{2})$

$M=(5,2)$

Therefore, the mid point of HJ is (5,2).