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sashaice [31]
3 years ago
10

4x-5y=5 -0.08+0.10y=0.10 How many solution or there to the system of equations?

Mathematics
2 answers:
iVinArrow [24]3 years ago
7 0
An infinate amount of solutions
Inessa [10]3 years ago
6 0

Answer:

A) no solution

Step-by-step explanation:

The given system of equations are:

4x - 5y = 5

-0.08x + 0.10y  = 0.10

Let's find the slope of the each equation.

4x - 5y = 5

Write the equation in slope-intercept form y = mx + b.

-5y = -4x + 5

Dividing both sides by -5, we get

y = -4/-5 x +5/-5

y = 0.8x - 1

Here slope = 0.8 and y-intercept (b) = -1

-0.08x + 0.10y = 0.10

0.10y = 0.08x + 0.10

Divide both side by 0.10, we get

y = 0.8x + 1

Here the slope = 0.8 and y-intercept (b) = 1

From the both the equations, the slopes are the same and y-intercepts are different.

Therefore, the given system of equations are parallel.

If the system of equations are parallel, then there is no solution.

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Hi there!

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