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Anna71 [15]
3 years ago
5

Postulates need to be proven.

Mathematics
2 answers:
spin [16.1K]3 years ago
8 0
False postulates dont need to be proven
Effectus [21]3 years ago
6 0
False, a postulate is already proven to be true.
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Help i'll make you the brainliest
9966 [12]

Answer:

D) b = \frac{S-2ac}{2a + 2c}

Step-by-step explanation:

First, move all the terms that do not include b to the left side with S:

S = 2ab + 2bc + 2ac

S - 2ac = 2ab + 2bc

Now, factor out 2b from the right side:

S - 2ac = 2b(a + c)

Divide both sides by 2(a + c):

b = \frac{S-2ac}{2(a + c)}

Finally, multiply out the denominator:

b = \frac{S-2ac}{2a + 2c}

7 0
3 years ago
00:00
Aleks04 [339]

Answer:

Figure A is a  translation of Figure 1

hope it helps...

7 0
3 years ago
A factorial experiment was designed to test for any significant differences in the time needed to perform English to foreign lan
yuradex [85]

Answer:

For main effects

Factor (Language translator) confirms that there is no significance difference between two levels of language translator of main effect at 5% level of significance.

Factor (Types of language) confirms that there is no significance difference between three levels of types of language at 5% level of significance.

also,

For interaction effect between language translator and types of language, there is no significant difference that the interaction between language translator and types of language at 5% level of significance.

Step-by-step explanation:

see attached.

3 0
3 years ago
How many integers between 10000 and 99999, inclusive, are divisible by 3 or<br> 5 or 7?
Yuki888 [10]

Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) = \dfrac{90000}{3}=30000

n( divisible by 5) = \dfrac{90000}{5}=18000

n( divisible by 7) = \dfrac{90000}{7}=12857.14

n( divisible by 3 and 5) = n(3∩5)=\dfrac{90000}{15}=6000

n( divisible by 5 and 7) = n(5∩7) = \dfrac{90000}{35}=2571.42

n( divisible by 3 and 7) = n(3∩7) = \dfrac{90000}{21}=4285.71

n( divisible by 3,5 and 7) = n(3∩5∩7) = \dfrac{90000}{105}=857.14

As we know the formula,

n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

=30000+18000+12857.14-6000-2571.42-4258.71+857.14\\\\=48884.15

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

5 0
3 years ago
Which absolute value expression represents the distance between 1.7 and -1/2
aleksley [76]

Answer: None of the above

Step-by-step explanation: Because none of them will equal the solution which is 0.5,

1.7 + (-1.2) = 0.5

3 0
3 years ago
Read 2 more answers
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