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4 years ago

If ABC is a right triangle, and m∠A=40º, what are possible measures for B and C? (I forgot the screenshot so sowy ;w;*

Mathematics

2 answers:

weqwewe [10]4 years ago

8 0

Answer:

The other possible angles would be 90º (Right tringles always have a 90º angle) and 50º

Step-by-step explanation:

To find the 3rd angle (the 50º one) all tringles angles add up to 180º. Since you already have 40º and 90º

you would subtract those from 180.

180º - 40º - 90º = 50º

Lapatulllka [165]4 years ago

6 0

There is many answers to this question but angle B and C have to add up to 140 so angle B and C could both be 70 that should work

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When 3 times a number is subtracted from 10, the result is the sum of the number and 22

Arada [10]

Answer:

x = -6

Step-by-step explanation:

Let the number be x

Condition:

=> 10-3x = x+22

Let's Solve it:

=> -3x-x = 22-10

=> -2x = 12

Dividing both sides by -2

=> x = -6

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4 years ago

Read 2 more answers

What’s 3x+6y=12 in the form y=mx+b

zhenek [66]

Hey there!

3x+6y=12

Divide both sides by 3 and your equation would now look like:
x+2y= 4
Move the x to the other side
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Seprate the y by dividing both sides by 2
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3 years ago

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Someone help me plz!!

likoan [24]

Answer: x=15

Step-by-step explanation:

Since these are supplementary angles, we know that if we add them together we would get 180 deg. so....

(7x-10)+ (6x-5)=180

Kay so now we can combine like terms.

13x-15=180

Now we can add 15 to both sides.

13x=195

Finally Divide 13 on both sides.

X would then now equal 15.

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3 years ago

A certain fraction is greater than 2. The denominator is 8. What must be true about the numerator?

Volgvan

Answer:

The numerator must be greater than 16

Step-by-step explanation:

We are told that a certain fraction is greater than 2. Thus, if the numerator and denominator are x and y respectively, then we have;

x/y > 2

We are further told that the denominator is 8.

Thus;

x/8 > 2

Multiply both sides by 8 to give;

x > 16

Thus,the numerator must be greater than 16.

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