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dimulka [17.4K]
3 years ago
5

If ABC is a right triangle, and m∠A=40º, what are possible measures for B and C? (I forgot the screenshot so sowy ;w;*

Mathematics
2 answers:
weqwewe [10]3 years ago
8 0

Answer:

The other possible angles would be 90º (Right tringles always have a 90º angle) and 50º

Step-by-step explanation:

To find the 3rd angle (the 50º one) all tringles angles add up to 180º. Since you already have 40º and 90º

you would subtract those from 180.

180º - 40º - 90º = 50º

Lapatulllka [165]3 years ago
6 0
There is many answers to this question but angle B and C have to add up to 140 so angle B and C could both be 70 that should work
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\huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }

\large\underline{  \boxed{ \sf{✰\:Important\: point's }}}

  • ➢Given two lines are intersecting lines
  • ➢ as it's clearly known when two or more lines meet each other at a specific points is said to be as intersecting lines nd they must be having a common point
  • ➢Here angle t and angle 120⁰ forms adjacent angles
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{ \rule{70mm}{2.9pt}}

\underline{  \boxed{ \sf{✵\: let's\: solve\:✵}}}

\sf ➛\angle \: 120 \degree + \angle \:t  = 180\degree \\   \sf ➛\angle  \:t = 180 \degree -   \angle \:120 \degree \\   \sf ➛\angle \: t =  \:60 \degree

{ \rule{70mm}{2.9pt}}

\boxed{✛\underline{  \boxed{ \sf{ \: \angle \: t = 60 \degree  \: }}}✛}

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