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2 years ago

What is the inverse of the function f(x)= 19/x^3 ?

1 answer:

8 0

$f(x)=\dfrac{19}{x^3}\to y=\dfrac{19}{x^3}\\\\\dfrac{y}{1}=\dfrac{19}{x^3}\ \ \ \ |cross\ multiply\\\\yx^3=19\ \ \ \ |:y\neq0\\\\x^3=\dfrac{19}{y}\to x=\sqrt[3]{\dfrac{19}{y}}$
Answer: $f^{-1}(x)=\sqrt[3]{\dfrac{19}{x}}$

You might be interested in

Figure ABCD is similar to figure MNKL. Write a proportion that contains BC and KL.

joja [24]

B/C = K/L because they are similar

7 0

3 years ago

Suppose that 10% of the undergraduates at a certain university are foreign students, and that 25% of the graduate students are f

Deffense [45]

Answer:

0.6154 = 61.54% probability that the student is an undergraduate

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Foreign

Event B: Undergraduate.

There are four times as many undergraduates as graduate students

So 4/5 = 80% are undergraduate students and 1/5 = 20% are graduate students.

Probability the student is foreign:

10% of 80%

25% of 20%. So

$P(A) = 0.1*0.8 + 0.25*0.2 = 0.13$

Probability that a student is foreign and undergraduate:

10% of 80%. So

$P(A \cap B) = 0.1*0.8 = 0.08$

What is the probability that the student is an undergraduate?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.08}{0.13} = 0.6154$

0.6154 = 61.54% probability that the student is an undergraduate

8 0

2 years ago

Please do this I need help ASAP

Doss [256]

Answer:

y-5=3 can be the correct answer

3 0

3 years ago

Find the area. Round to the nearest hundredth when necessary. Be sure you are showing all work to find each figure.

eimsori [14]

Additional requirements in figure :-

Mark point :-

Draw a straight line from E to AB .

And the point line joins mark it as "F" .

It will generate quadrilateral FBCD.

we get to know In quadrilateral left angle is 90°

How ?

{

proof :

As three angles are given 90° So third angle will also be 90°

Reason:

→ Sum of interior angles = 2 (no. of angles - 2 × 180°

→Sum of interior angles = (4-2 × 180°)

→Sum of interior angles = (2 × 180°)

→Sum of interior angles = 360°

}

✿Now let the left angle be x

90° +90° + 90° + x = 360°
180° + 90° + x = 360°
270° + x = 360
x = 360° - 270°
x = 90°

we know :

Area of rectangle = Length × Breadth

STEPS :

Area of rectangle = Length × Breadth

Area of rectangle = 7 × 8

Area of rectangle = 56 in²

Now let's find EF :

EF = BD - EC

EF = 7 - 4

EF = 3 in

To find A

F :

A•F = AB - CD

A•F = 12 - 8

A•F = 4 in

In triangle AFE:

EF is base of triangle
A•F is height of triangle

We know :

Area of triangle =( Height × Base)/2

Steps :

Area of triangle = (Height × Base)/2
Area of triangle = (4 × 3)/2
Area of triangle = 12/2
Area of triangle = 6 in²

To find area of figure :

Area of figure = Area of rectangle + Area of triangle
Area of figure = 56 + 6
Area of figure = 62 in²

______________________

~WindyMint

5 0

1 year ago

DASAROLLA: a) (x+3) (x+5)= b) (x+4) (x-5)=

Nat2105 [25]

Answer:

a) $x^{2}$ +8x+15

b) $x^{2}$ -x-20

Step-by-step explanation:

a) (x+3)(x+5)

a) $x^{2}$ +5x+3x+15

a) $x^{2}$ +8x+15

b) (x+4)(x-5)

b) $x^{2}$ -5x+4x-20

b) $x^{2}$ -x-20

8 0

2 years ago