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levacccp [35]
3 years ago
6

Y=1/2x+2 I need to find the slope.

Mathematics
2 answers:
topjm [15]3 years ago
5 0

Answer:

1/2x + 2 = 5/2x

Step-by-step explanation:

You have to find the LCD, which is 2, then 1/2 X 2 for the top and bottom and then turn 2 into a 2/1 X 1 = 4/2. Then add 1/2 + 4/2 = 5/2x :)

gtnhenbr [62]3 years ago
4 0

Answer:

Hey there!

This is in y=mx+b form, where m is the slope. 1/2 is the slope.

Hope this helps :)

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one month salary = £1410
so 12 month salary = £1410 x 12 = £16920
2) 26% of total profit
Total cost to the company- £473,500
Total income for the company - £549,000
Profit = Total income for the company - Total cost to the company
= £549,000 - £473,500 = £75500
Sues income from profit = 26% of £75500 = (26 × 75500)/100 = £19630
3) Bonus if Sue sells at least 16 cars
Given number of months when sue solds atleast 16 cars = 4
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Adding the three above parts
Sue's total pay for the year = £16920 + £19630 + £1560 = £38110
8 0
2 years ago
Estimate the sum <br><br> 1.37 + 0.9
guajiro [1.7K]

1.37 + 0.9\\\\\\=\dfrac{137}{100} + \dfrac{9}{10}\\\\\\=\dfrac{137}{100}+\dfrac{90}{100}\\\\\\=\dfrac{137+90}{100}\\\\\\=\dfrac{227}{100}\\\\\\=2.27

8 0
2 years ago
"Two-thirds of a number is<br> negative 20.
ExtremeBDS [4]
The number is -30
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7 0
2 years ago
If mMVUW=(4x+6)° and mWUT=(6x+10)°, what is the measure of WUT
FinnZ [79.3K]

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WUT = WUV

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Putting the value of x in the Angle WUT

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2 years ago
Suppose the national mean SAT score in mathematics was 510. In a random sample of 60 graduates from Stevens High, the mean SAT s
zalisa [80]

Answer:

We accept the alternate hypothesis and conclude that mean SAT score for Stevens High graduates is not the same as the national average.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 510

Sample mean, \bar{x} = 502

Sample size, n = 60

Sample standard deviation, s = 30

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

H_{0}: \mu = 510\\H_A: \mu \neq 510

We use Two-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n-1}} } Putting all the values, we have

t_{stat} = \displaystyle\frac{502- 510}{\frac{30}{\sqrt{60}} } = -2.0655

Now,

t_{critical} \text{ at 0.05 level of significance, 59 degree of freedom } = \pm 1.671

Since,              

|t_{stat}| < |t_{critical}|

We reject the null hypothesis and fail to accept it.

We accept the alternate hypothesis and conclude that mean SAT score for Stevens High graduates is not the same as the national average.

7 0
2 years ago
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