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3 years ago

Find the constant of proportionality for the table of values.

Mathematics

1 answer:

Anna [14]3 years ago

4 0

The constant of proportionality k is 3.5

Step-by-step explanation:

Proportionality describes any relationship that is always in the same

ratio

If two quantities x and y are in proportionality, then

1. y ∝ x

2. y = k x , where k is the constant of proportionality

∵ x ⇒ 6 , 7 , 8 , 9

∵ y ⇒ 21 , 24.5 , 28 , 31.5

∵ y ∝ x

∴ y = k x

- Use x = 6 and y = 21 to find the value of k

∵ x = 6 and y = 21

∴ 21 = k (6)

- Divide both sides by 6

∴ k = 3.5

- Use x = 7 and y = 24.5 to find the value of k

∵ x = 7 and y = 24.5

∴ 24.5 = k (7)

- Divide both sides by 7

∴ k = 3.5

- Use x = 8 and y = 28 to find the value of k

∵ x = 8 and y = 28

∴ 28 = k (8)

- Divide both sides by 8

∴ k = 3.5

- Use x = 9 and y = 31.5 to find the value of k

∵ x = 9 and y = 31.5

∴ 31.5 = k (9)

- Divide both sides by 9

∴ k = 3.5

The constant of proportionality k is 3.5

Learn more:

You can learn more about proportionality in brainly.com/question/10708697

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3 years ago

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3 years ago

A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 31 ft/s. (a) A

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Answer:

a) -13.9 ft/s

b) 13.9 ft/s

Step-by-step explanation:

a) The rate of his distance from the second base when he is halfway to first base can be found by differentiating the following Pythagorean theorem equation respect t:

$D^{2} = (90 - x)^{2} + 90^{2}$ (1)

$\frac{d(D^{2})}{dt} = \frac{d(90 - x)^{2} + 90^{2})}{dt}$

$2D\frac{d(D)}{dt} = \frac{d((90 - x)^{2})}{dt}$

$D\frac{d(D)}{dt} = -(90 - x) \frac{dx}{dt}$ (2)

Since:

$D = \sqrt{(90 -x)^{2} + 90^{2}}$

When x = 45 (the batter is halfway to first base), D is:

$D = \sqrt{(90 - 45)^{2} + 90^{2}} = 100. 62$

Now, by introducing D = 100.62, x = 45 and dx/dt = 31 into equation (2) we have:

$100.62 \frac{d(D)}{dt} = -(90 - 45)*31$

$\frac{d(D)}{dt} = -\frac{(90 - 45)*31}{100.62} = -13.9 ft/s$

Hence, the rate of his distance from second base decreasing when he is halfway to first base is -13.9 ft/s.

b) The rate of his distance from third base increasing at the same moment is given by differentiating the folowing Pythagorean theorem equation respect t:

$D^{2} = 90^{2} + x^{2}$