Answer:
- 2 groups of 6
- 6 groups of 2
- 4 groups of 3
- 3 groups of 4
- 1 group of 12
- 12 groips of 1
Step-by-step explanation:
To figure out the possible groups find the factors of 12; in other words what two numbers would multiply to 12. These are: 1, 2, 3, 4, 6, and 12
- 1 × 12 = 12
- 2 × 6 = 12
- 3 × 4 = 12
- 4 × 3 = 12
- 6 × 2 = 12
- 12 × 1 = 12
So, your possible groupings are;
- 2 groups of 6
- 6 groups of 2
- 4 groups of 3
- 3 groups of 4
- 1 group of 12
- 12 groips of 1
Answer:

Step-by-step explanation:




Rise is 35, run is 1
35 is the answer
Answer:
21
Step-by-step explanation:
Answer
Length = 10 ft
Width = 5 ft
Explanation
Area of the rectangle given = 50 ft²
Let the width of the rectangle be x
So this means the length of the rectangle will be 3x - 5
What to find:
The dimensions of the rectangle.
Step-by-step solution:
Area of a rectangle = length x width
i.e A = L x W
Put A = 50, L = 3x - 5, W = x into the formula.

The quadratic equation can now be solve using factorization method:

Since the dimension can not be negative, hence the value of x will be = 5.
Therefore, the dimensions of the rectangle will be: