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igor_vitrenko [27]
3 years ago
9

Help me ???? plzzzzzzzzzzz

Mathematics
1 answer:
Yuri [45]3 years ago
3 0
Your answer will be this 2)4.10
5)30.00
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5 ( x + 7 ) +2 ( y - 1 ) when x=7 and y=2
noname [10]

Answer:

Step-by-step explanation:

5(x+7) + 2(y-1)

here x=7 and y=2

so 5(7+7)+2(2-1)= 5*14+ 2*1

70+2=72

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4 years ago
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The coordinates of the point that is a reflection of Y(-4,-2) across the x-axis are what. The coordinates of the point that is r
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Answer:

Step-by-step explanation:

across x axis:(-4,2)

across y-axis:(4,-2)

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Solve the equation.<br><br> 5=w2.2
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Answer:

The answer is about 2.27

Step-by-step explanation:

Hope this help <3

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3 years ago
The distance from the library to the park is your point 7 km how many meters is this
sattari [20]

Answer:

7000 meters

Step-by-step explanation:

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5 0
3 years ago
The time between arrivals of taxis at a busy intersection is exponentially distributed with a mean of 10 minutes. (a) What is th
Sindrei [870]

Answer:

a) 0.0025

b) 0.9975

c) 23.03 minutes

d) 23.03 minutes

Step-by-step explanation:

Let X be the random variable that measures the time waited for a taxi.  

If X is exponentially distributed with a mean of 10 minutes,then the probability that you have to wait more than t minutes is  

\large P(X>t) = e^{-t/10}

a)  

1 hour = 60 minutes, so the probability that you wait longer than one hour is

\large P(X>60)=e^{-6}=0.0025

b)

Due to the “memorylessness” of the exponential distribution, the probability that you have to wait 10 or less minutes after you have already waited for one hour, is the same as the probability that you have to wait 10 or less minutes

\large P(X\leq 10)=1-e^{-6}=0.9975

c)

We want x so that

P(X>x)=0.1

\large e^{-x/10}=0.1\rightarrow -x/10=ln(0.1)\rightarrow x=-10ln(0.1)=23.03\;minutes

d)

We want P(X<x)=0.9

\large 1-e^{-x/10}=0.9\rightarrow e^{-x/10}=0.1\rightarrow x=-10ln(0.1)=23.03\;minutes

4 0
3 years ago
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