we know that
The measurement of <u>the external angle</u> is the semi-difference of the arcs it includes.
In this problem
![21\°=\frac{1}{2}[arc\ RU-arc\ SU]](https://tex.z-dn.net/?f=21%5C%C2%B0%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20RU-arc%5C%20SU%5D)
Solve for the measure of arc SU
![42\°=[arc\ RU-arc\ SU]](https://tex.z-dn.net/?f=42%5C%C2%B0%3D%5Barc%5C%20RU-arc%5C%20SU%5D)
therefore
the answer is
The measure of the arc SU is 
Answer:
8.3
Step-by-step explanation:
8.25 has to round up because of the five making it 8.3
Answer:
20
Step-by-step explanation:
they are proportional
so, since width increases by 4 times, length also increases by 4times
Answer:
3
Step-by-step explanation:
Answer:
A) (x − 2)2 + (y + 1)2 = 16
please give me brainliest
Step-by-step explanation:
center: (2, −1)
(x − 2)2 + (y + 1)2
radius: 4
4^2 = 16
