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tangare [24]
3 years ago
8

What is the y-value when x equals 28? y=330-40(x)

Mathematics
2 answers:
shtirl [24]3 years ago
6 0
To find the answer, you would replace the value of x with 28 in the equation, Making it y=330-4 (28).
You would multiply to get 1, 120, then subtract from 330. Resulting in, y= -790.
Arisa [49]3 years ago
4 0
Plug in 28 for x
then do 40 times 28 which is 1120
then do 330-1120 which gets you
-790
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2 years ago
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What equation relates the number of quarters x and the number of quarters x and the number of dime y to the goal of $10
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.25x+.10y=$10

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8 0
3 years ago
Given the figure above, determine​
tensa zangetsu [6.8K]
Answer: Angle 2 = 47 degree

Explanation:

Proof that triangle ACB ~ triangle CBD

Angle ABC = Angle CBD (same angle)

If one pair of the angle is the same then the other pair should also be equal because both the triangle are Isosceles.

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But angle A = 47 degree

Therefore, Angle C = Angle 2 = 47 degree

6 0
2 years ago
One cubic meter of water weighs approximately 2200 pounds. There are 100 cm in one meter. If you have a box-shaped fish tank tha
Diano4ka-milaya [45]

Answer:

158.4 pounds

Step-by-step explanation:

first find the volume of the tank

V = 30 \times 30 \times 80

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V = 72000 cm^3 \times \left(\dfrac{1\,\text{m}}{100\,\text{cm}}\right)^3

V = 72000 cm^3 \times \left(\dfrac{1\,\text{m}^3}{100^3\,\text{cm}^3}\right)

the cm^3 cancel out.

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by simply converting the side-lengths to meters beforehand can give you this answer directly:

V = 0.3 \times 0.3 \times 0.8 = 0.072 m^3

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multiply both sides with 0.072 to find our answer:

1\,m^3 \times 0.072 = 2200 \times 0.072 \,\text{lb}

0.072\,m^3 = 158.4 \,\text{lb}

hence the weight of the water in the tank would be 158.4 pounds!

3 0
3 years ago
2. If (300) (30,000) = 9 x 10m, then m =
Rufina [12.5K]
(300) (30,000) = 9 x 10m
9,000,000 = 90m
divide by 90
100,000 = m
6 0
2 years ago
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