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3 years ago

14

What is the distance, in radical form, between the points (4,6) and (8,-2)?

1 answer:

kozerog [31]3 years ago

6 0

$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} \\d = \sqrt{(8 - 4)^{2} + (-2 - 6)^{2}} \\d = \sqrt{(4)^{2} + (-8)^{2}} \\d = \sqrt{16 + 64} \\d = \sqrt{80} \\d = \sqrt{16 * 5} \\d = \sqrt{16}\sqrt{5} \\d = 4\sqrt{5}$

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Can you solve this ? Thanks

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3 years ago

Need help with this

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2 years ago

How do I solve the literal equation 6=mx+b for x? Did not learn this in school as I was absent for two weeks.

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3 years ago

Francis works at Carlos Bakery and is making cookie trays. She has 48 chocolate chip cookies, 64 rainbow cookies, and 120 oatmea

amm1812

The number of cookies and trays are illustrations of greatest common factors.

The number of trays is 8
6 chocolate chips, 8 rainbows and 15 oatmeal cookies would fit each tray

The given parameters are:

$\mathbf{Chocolate\ chip=48}$

$\mathbf{Rainbow=64}$

$\mathbf{Oatmeal=120}$

<u>(a) The number of trays</u>

To do this, we simply calculate the greatest common factor of 48, 64 and 120

Factorize the numbers, as follows:

$\mathbf{48 = 2 \times 2 \times 2 \times 2 \times 3}$

$\mathbf{64 = 2 \times 2 \times 2 \times 2 \times 2 \times 2}$

$\mathbf{120 = 2 \times 2 \times 2 \times 3 \times 5}$

So, the GCF is:

$\mathbf{GCF= 2 \times 2 \times 2}$

$\mathbf{GCF= 8}$

Hence, the number of tray is 8

<u>(b) The number of each type of cookie</u>

We have

$\mathbf{Chocolate\ chip=48}$

$\mathbf{Rainbow=64}$

$\mathbf{Oatmeal=120}$

Divide each cookie by the number of trays

So, we have:

$\mathbf{Chocolate\ chip = \frac{48}{8} = 6}$

$\mathbf{Rainbow = \frac{64}{8} = 8}$

$\mathbf{Oatmeal = \frac{150}{8} = 15}$

Hence, 6 chocolate chips, 8 rainbows and 15 oatmeal cookies would fit each tray

Read more about greatest common factors at:

brainly.com/question/11221202

4 0

2 years ago

What is the coefficient of x in 4x/5 a)1/5 b.5 c.4/5 d.4 e.-0.8

almond37 [142]

Answer:

C

$\frac{4}{5}$

Co efficient means the number or value beside preventing the variable from standing alone

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3 years ago

Read 2 more answers