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2 years ago

Help? I will be grateful!

Mathematics

1 answer:

Airida [17]2 years ago

3 0

<h3>Answer: 11/24</h3>

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Explanation:

Let's say we had 12 skateboards and 12 scooters. I'm picking 12 because 4*3 = 12 after multiplying the denominators. Doing this trick will mean we end up with whole number results instead of decimals.

If we had 12 skateboards, then (1/4)*12 = 3 of them are red. Having 12 scooters means (2/3)*12 = 8 scooters are red.

Add up the counts of each red item to get 3+8 = 11 red items out of 12+12 = 24 items total. Therefore, the answer is 11/24

Side note: The fraction 11/24 cannot be reduced because 11 and 24 have no factors in common other than 1.

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Elimination method: ax+by=r, -bx+cy=s

Alex17521 [72]

$\left[\begin{array}{ccc}ax+by=r\\\\-bx+cy=s\end{array}\right]$

Isolate x for $ax+by=r$

$x= \frac{r-by}{a} ; a \neq 0$

Subsititute $x= \frac{r-by}{a}$

$-b \frac{r-by}{a} +cy=s$

Isolate r for : $-b \frac{r-by}{a}+cy=s$

$r=- \frac{as-acy-b^2y}{b} ; a \neq 0;b \neq 0$

For x : $\frac{r-by}{a}$

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$x= -\frac{as-acy-b^2y}{b}/a$

$x = \frac{cy-s}{b}$

The solutions to the system of equations are:

$r= -\frac{as-acy-b^2y}{b}$ and <span> $x = \frac{cy-s}{b}$
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3 years ago

for a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height,

kolbaska11 [484]

Problem

For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground

Solution

We know that the x coordinate of a quadratic function is given by:

Vx= -b/2a

And the y coordinate correspond to the maximum value of y.

Then the best options are C and D but the best option is:

D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a

The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.

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1 year ago