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3 years ago

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Which data set has an outlier? 6, 13, 13, 15, 15, 18, 18, 22 4, 4, 4, 8, 9, 9, 11, 18 2, 3, 5, 7, 8, 8, 9, 10, 12, 17 3, 6, 7, 7

, 8, 8, 9, 9, 9, 10

1 answer:

aev [14]3 years ago

7 0

The answer to your question is D

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8.5 rounded to nearest tenth

melomori [17]

The answer is 9.0 because 8.5 is above 5 and to the nearest tenth it would be 9.0

4 0

3 years ago

Which expression is equivalent to (5g^4+5g^3-17g^2+6g)-(3g^4+6g^3-7g^2-12)/g+2

ankoles [38]

Option C:

$2 g^{3}-5 g^{2}+6$

Solution:

Given expression:

$$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}$

To find which expression is equal to the given expression.

$$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}$

Expand the term $-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right):-3 g^{4}-6 g^{3}+7 g^{2}+12$

$$=\frac{5 g^{4}+5 g^{3}-17 g^{2}+6 g- 3 g^{4}-6 g^{3}+7 g^{2}+12}{g+2}$

Arrange the like terms together.

$$=\frac{5 g^{4}- 3 g^{4}+5 g^{3}-6 g^{3}-17 g^{2}+7 g^{2}+6 g+12}{g+2}$

$$=\frac{2 g^{4}- g^{3}-10 g^{2}+6 g+12}{g+2}$

Factor the numerator $2 g^{4}-g^{3}-10 g^{2}+6 g+12=(g+2)\left(2 g^{3}-5 g^{2}+6\right)$

$$=\frac{(g+2)\left(2 g^{3}-5 g^{2}+6\right)}{g+2}$

Cancel the common factor g + 2, we get

$=2 g^{3}-5 g^{2}+6$

Hence option C is the correct answer.

8 0

2 years ago

Read 2 more answers

A square is a quadrilateral always sometimes never

lbvjy [14]

A quadrilateral is a shape with 4 sides, regardless of their lengths, angles, or symmetry.

Therefore, a square is always a quadrilateral.

6 0

3 years ago

Read 2 more answers

Write the equation of the line perpendicular to 2x+3y=9 that passes through (-2,5). Write your answer in slope-intercept form. S

Harman [31]

ANSWER

$y = \frac{3}{2} x + 8$

EXPLANATION

The line given to us has equation,

$2x + 3y = 9$

We need to write this equation in the slope intercept form to obtain,

$3y = - 2x + 9$

$\Rightarrow \: y = - \frac{2}{3}x + 3$

The slope of this line is

$m_1 = - \frac{2}{3}$
Let the slope of the perpendicular line be

$m_2$

Then
$m_1 \times m_2 = - 1$

$- \frac{2}{3} m_2= - 1$

This implies that,

$m_2 = - 1 \times - \frac{3}{2}$

$m_2 = \frac{3}{2}$

Let the equation of the perpendicular line be,

$y = mx + b$

We substitute the slope to get,

$y = \frac{3}{2} x + b$

Since this line passes through
$(-2,5)$
it must satisfy its equation.

This means that,

$5= \frac{3}{2} ( - 2)+ b$

$5 = - 3 + b$

$5 + 3 = b$

$b = 8$

Wherefore the slope-intercept form is

$y = \frac{3}{2} x + 8$

6 0

3 years ago

A cylindrical container has a radius of 0.3 meter and a height of 0.75 meter. The container is filled with kerosene. The density

saveliy_v [14]

Answer:

172.83 kg

Step-by-step explanation:

A cylindrical container has a radius (r) of 0.3 meter and a height (h) of 0.75 meter and density of 815 kg/m³.

The density of a substance is the mass per unit volume, it is the ratio of the mass of a substance to the volume occupied. The density is given by the formula:

Density = Mass / volume

The volume of a cylinder is given as:

V = πr²h

V = π × (0.3)² × 0.75 = 0.212 m³

Density = Mass/ volume

Mass = Density × Volume

Mass = 815 kg/m³ × 0.212 m³

Mass = 172.83 kg

6 0

2 years ago