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3 years ago

How to find the area of a triangle with given coordiantes? #5-50

Mathematics

1 answer:

AlexFokin [52]3 years ago

8 0

Use the coordinates and plot them. On the graph, count the weight and height.

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The ratio of the number of boy campers to the number of girl campers was 8:7. If there were a total of 195 campers, how many boy

kupik [55]

8x - amount of boys
7x- amount of girls

8x + 7x = 195

15x= 195 ( divide by 15)

x= 13

8x = 8 x 13 = 104

7x = 7 x 13= 91

there are 104 boys, and 91 girls.

4 0

3 years ago

A ball is floating partially submerged in a liquid. Which quantity equals the buoyant force acting on the ball? mass of the ball

REY [17]

For something to float the buoyant force ( force pushing up on the object to keep it floating) needs to equal the weight of the object

the answer would be: <span>weight of the ball</span>

6 0

3 years ago

Carissa also has a sink that is shaped like a half-sphere. The sink has a volume of 2000/3[pie] in^3. One day, her sink clogged.

Kobotan [32]

I have these same questions but the way i solved them i did

A: 1/3 x 3.14 x 2*2 x 8 = 32/3 = 2000 divided by 32 = 63 scoops
The formula is 1/3 x 3.14 x r*2 x h
B: 1/3 x 3.14 x 8*2 x 8 = 128/3 = 2000 divided by 128 = 16 scoops

8 0

3 years ago

Hello I was wondering what is the m

oee [108]

Angles in a triangle add up to 180 therefore:

Angle CAB = 180 - 60 - 50 = 70

Angles on a straight line add up to 180 therefore the missing angle is:

180 -70 = 110

Answer is D

I hope this has helped you today, please rate as brainliest if you think this helped you understand the question.

Have a great day!

5 0

3 years ago

Given LaTeX: f\left(x\right)=x^{^3}-3x+4f ( x ) = x 3 − 3 x + 4, determine the intervals where the function is increasing and wh

Vedmedyk [2.9K]

Answer:

Increasing: $x$ and $x>1$ .

Decreasing: $-1$

Step-by-step explanation:

We have been given a function $f(x)=x^3-3x+4$ . We are asked to determine the intervals, where the function is increasing and where it is decreasing.

First of all, we will find critical points of our given function by equating derivative of our given function to 0.

Let us find derivative of our given function.

$f'(x)=\frac{d}{dx}(x^3)-\frac{d}{dx}(3x)+\frac{d}{dx}(4)$

$f'(x)=3x^{3-1}-3+0$

$f'(x)=3x^{2}-3$

Let us equate derivative with 0 as find critical points as:

$0=3x^{2}-3$

$3x^{2}=3$

Divide both sides by 3:

$x^{2}=1$

Now we will take square-root of both sides as:

$\sqrt{x^{2}}=\pm\sqrt{1}$

$x=\pm 1$

$x=-1,1$

We know that these critical points will divide number line into three intervals. One from negative infinity to -1, 2nd -1 to 1 and 3rd 1 to positive infinity.

Now we will check one number from each interval. If derivative of the point is greater than 0, then function is increasing, if derivative of the point is less than 0, then function is decreasing.

We will check -2 from our 1st interval.

$f'(-2)=3(-2)^{2}-3=3(4)-3=12-3=9$