Answer:
Step-by-step explanation:
Let n = the smaller of the two numbers, and since the other number is 5 more than twice the smaller number n, then ...
Let 2n + 5 = the second and larger number.
Since the sum of the two unknown numbers is 26, then we can write the following equation to be solved for n as follows:
n + (2n + 5) = 26
n + 2n + 5 = 26
Collecting like-terms on the left, we get:
3n + 5 = 26
3n + 5 - 5 = 26 - 5
3n + 0 = 21
3n = 21
(3n)/3 = 21/3
(3/3)n = 21/3
(1)n = 7
n = 7
Therefore, ...
2n + 5 = 2(7) + 5
= 14 + 5
= 19
CHECK:
n + (2n + 5) = 26
7 + (19) = 26
7 + 19 = 26
26 = 26
Therefore, the two desired numbers whose sum is 26 are indeed 7 and 19.
Since it's asking you to write a problem about a sharing division "situation", I'm assuming the picture above it is part of #4 so you could use that as a reference as well.
You could do 2 divided by 5 which is left with a remainder. So it could be like, "Jack has 5 cookies and wants to share with his friends, he wants to give each of his two friends 2 cookies each".. Something like that and you go ahead and solve it. The final answer will be the solution to your word problem. I hope this helped
Answer:
1655
Step-by-step explanation:
Note the common difference d between consecutive terms of the sequence
d = - 1 - (- 4) = 2 - (- 1) = 5 - 2 = 8 - 5 = 3
This indicates the sequence is arithmetic with sum to n terms
= 
[ 2a₁ + (n - 1)d ]
Here a₁ = - 4, d = 3 and n = 90, thus
= 
[ (2 × - 4) + (89 × 3) ] = 45(- 8 + 267) = 45 × 259 = 1655
