No matter what number you substitute for y, this equation will be untrue.
It has zero solutions.
To solve this you first expand the brackets.
4x^2 - 20x + 25 = 49
Then make it equal 0.
4x^2 - 20x - 24 = 0
Now solve the quardratic.
x^2 - 5x - 6 = 0
(x - 6)(x + 1) = 0
x = 6 or x = -1
I believe it is neither
For one if you plug in either of them the first one is going to be negative 3. But if you use the second one then your answer would be -3+12= -10 but -3+12 is 9 so I would go with neither because I don't see how it's both
Answer:
it's just 8/20 so shade 8/20 of the circle
Answer:
x = 2root(22)
see image.
Step-by-step explanation:
The triangle shown is one big triangle cut into two more smaller triangles: one medium-sized and one smaller.
ALL THREE TRIANGLES ARE SIMILAR BY AA.
Set the two smaller triangles up so you can see the corresponding sides. x is the short leg in one triangle and it is the long leg in the smallest triangle. Set up a proportion.
22/x = x/4
crossmultiply
x^2 = 22•4
x^2 = 88
square root both sides.
x = sqroot(88)
x = 2sqroot(22)
see image.