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anzhelika [568]
3 years ago
15

Emma's final grade in her math class is the average (mean) of her 5 chapter tests she took throughout the year. If she received

a 92%, 85%, 78%, 97%, and 88% on the five tests, what is her final grade?​
Mathematics
2 answers:
NikAS [45]3 years ago
8 0

Answer:

Step-by-step explanation:

The mean (or average) of a set of numbers can be found with the following formula:

Mean = \frac{A_{1} + A_{2} + ... + A_{N}}{N}

For this problem, we have five numbers, so we add them together and divide by 5:

Mean = \frac{92 + 85 + 78 + 97 + 88}{5}

Mean = \frac{440}{5}

Mean = 88

boyakko [2]3 years ago
5 0

Answer:

88%

Step-by-step explanation:

Emma took tests of her 5 chapters throughout the year.

She received  the score on the five tests

92%, 85%, 78%, 97% and 88%

We have to calculate the average (mean) of her final grade.

average =  \frac{\text{addition of all grades}}{\text{total number of tests}}

=  \frac{92+85+78+97+88}{5}

=  \frac{440}{5}

= 88%

Her final grade would be 88%.

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1 day

4 0
2 years ago
Stefan sells Jim a bicycle for $175 and a helmet for $17. The total cost for Jim is 160% of what Stefan spent originally to buy
Nady [450]

Answer:

Stefan spend $120 originally.

Stefan made $72 by selling bicycle and helmet to Jim.

Step-by-step explanation:

Given:

Cost of bicycle = $175

Cost of Helmet = $17

Percent of total cost of Jim = 160% of original cost of Stefan

We need to find the Amount Stefan spend originally and money he made by selling the bicycle and helmet to Jim.

Solution:

Let the Amount Stefan spend originally be 'x'.

Total Cost of Jim is equal to sum of Cost of bicycle and Cost of Helmet.

framing in equation form we get;

Total Cost of Jim = 175+17 =\$192

Now we know that;

Total Cost of Jim is equal to 160% of  Amount Stefan spend originally.

framing in equation form we get;

192 = \frac{160}{100}\times x\\\\192 =1.6x

Dividing both side by 1.6 we get;

\frac{192}{1.6}=\frac{1.6x}{1.6}\\\\x= \$120

Hence Stefan spend $120 originally.

Now we can say that;

Money Stefan made is equal to Money Stefan spend originally minus Total Cost of Jim.

framing in equation form we get;

Money Stefan made = 192-120 =\$72

Hence Stefan made $72 by selling bicycle and helmet to Jim.

7 0
4 years ago
Four swimmers, Daniela, Camille, Brennan, and Amy, compete on a relay team. For the first race of the year, Daniela begins the r
Ad libitum [116K]

Answer:

A = {CBA, CAB, BCA, ACB}

Step-by-step explanation:

7 0
3 years ago
Part 3 - Discussion/Explanation Question
SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0
2 years ago
Which statement is true about the given information?
Lubov Fominskaja [6]

Answer

∴ The true statement is Answer:

The true statement is BD ≅ CE  ⇒ 3rd answer

Step-by-step explanation:

- There is a line contained points B , C , D , E

- All points are equal distance from each other

- That means the distance of BC equal the distance of CD and equal

 the distance of DE

∴ BC = CD = DE

- That means the line id divided into 3 equal parts, each part is one

  third the line

∴ BC = 1/3 BE

∴ CD = 1/3 BE

∴ DE = 1/3 BE

∵ BC = CD

∴ C is the mid-point of BD

∴ BC = 1/2 BD

∵ CD = DE

∴ D is the mid-point of DE

∴ CD = 1/2 CE

- Lets check the answers

* BD = one half BC is not true because BC = one half BD

* BC = one half BE is not true because BC = one third BE

* BD ≅ CE is true because

 BD = BC + CD

 CE = CD + DE

 BC ≅ DE and CD is common

 then BD ≅ CE

* BC ≅ BD is not true because BC is one half BD

∴ The true statement is BD ≅ CE

plz mark me brainliest

5 0
3 years ago
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