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n200080 [17]
3 years ago
8

Students in Miss Moseley's fourth grade class are learning multiplication, and they demonstrate mastery by passing assessments.

Travis has passed 11 tests, and his classmate, Jenifer, has passed 2 tests. Going forward, Travis plans to pass 2 tests per week. Meanwhile, Jenifer plans to pass 5 tests per week. Eventually Jenifer will catch up to Travis. When the number of tests each student has passed are equal, how many tests will each student have passed and how many weeks will it take?
Mathematics
2 answers:
noname [10]3 years ago
5 0
I think it is 3 weeks

const2013 [10]3 years ago
5 0
Its 3 weeks hope I helped

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What is the highest fraction here -3/25, -7 / 20, -27 / 50, -13 / 20, 16 / 25, 53 / 100, -1 / 3​
galina1969 [7]
16/25 is the highest, because if you multiply it by four you get 64/100, and the rest of the fractions are negative.
7 0
4 years ago
I NEED HELP ASAP THIS IS DUE AN IN HOUR ILL MARK U BRILY
ZanzabumX [31]

Answer:

74 °

Step-by-step explanation:

the sum of every angle from a triangle is 180

so to find b is add 80 with 26 which is 106

then subtract 180 with 106

the final answer is 74

7 0
3 years ago
A square is cut in half on the diagonal creating two equal triangle. Each triangle has an are of 1.32 square units. What is the
Ymorist [56]
What is the side length in unit of the original square?

Let's start by getting the area of the square.
The area of the square is the sum of the areas of the two triangles, or
2 x 1,32  = 2.64 square units.
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8 0
3 years ago
PLZ help I don't understand!!!!
WITCHER [35]

Answer:

5

Step-by-step explanation:

7 0
3 years ago
How do i solve for x? *you have to show work*
eduard
1) Factor the equation first:

2e^{2x} + 4xe^{2x} = 0
e^{2x}(2 + 4x) = 0

So either e^{2x} = 0 or 2 + 4x = 0. But e^{2x} = 0 can never equal 0! So, we only need to solve for the second equation:

2 + 4x = 0
\bf x = {-\frac{1}{2}}

2) First, single out the term with the exponent:

2 + 3(4^{2x - 1}) = 43
3(4^{2x - 1}) = 41
4^{2x - 1} = \frac{41}{3}

Now, taking the log base 4 of each side gives us

2x - 1 = \log_4 \frac{41}{3}

and we can now solve for x:

2x - 1 = \log_4 \frac{41}{3}
2x = 1 + \log_4 \frac{41}{3}
2x = \log_4 4 + \log_4 \frac{41}{3}
2x = \log_4 \frac{164}{3}
x = \frac{1}{2} \log_4 \frac{164}{3}
x = \log_4 \sqrt \frac{164}{3}
\bf x = \log_4 2 \sqrt \frac{41}{3}
8 0
3 years ago
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