The setup boxes in the synthetic division are (b)
<h3>How to determine the setup boxes?</h3>
The dividend is given as:
x^3 + 4x^2 + x - 6
The divisor is given as:
x - 2
Set the divisor to 0
x - 2 = 0
Solve for x
x = 2
Remove the variables in the dividend
1 + 4 + 1 - 6
Remove the arithmetic signs
1 4 1 - 6
So, the setup is:
2 | 1 4 1 - 6
Hence, the setup boxes are (b)
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Answer:
14+5 = 19
19 + 15/2
15/2 = 7.5
19+7.5 = 26.5
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Step-by-step explanation:
Answer:
1+1+2
Step-by-step explanation:
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Answer:
50m²
Explanation:
first, we have to find the length and width of the backyard. since 4cm represents 5m, we know that the real width of the backyard is 5m.
as for the length of the backyard, 8cm is double of 4cm so we can also double 5m to get 10m.
now, we can find the area by taking 5m × 10m = <u>50m²</u>.
i hope this helps! :D