Circle theorem:
The angle at the centre (T) is double the angle at the circumference (Q)
---> That also means that:
The angle at the circumference (Q) is <u>half</u> the angle at the centre (T)
Since T = 130 degrees;
Q = 130 divided by 2
= 65°
___________________________________
Answer:
∠Q = 65°
Answer: n=3
Step-by-step explanation:
Understand that you need to set up a proportion before you can try to solve the question through guessing. In this case, YZ would be proportional to XY as EF is proportional to DE. You would write this as: EF/DE=YZ/XY.
Now you want to write an equation. In order to do this remember to multiply by your proportion. Here’s my equation:
5/4(4n+4)=7n-1. Now distribute:
5n+5=7n-1. Now simplify:
6=2n. Now simplify again:
n=3
Hope this helps you with your big ideas math hw!
The value of R is 28° (Degrees), if the equation sin 62° = cos R true when 0° < R < 60°.
Step-by-step explanation:
The given is,
sin 62° = cos R
0° < R < 90°
Step:1
Form the given equation,
sin 62° = cos R.......................(1)
Where,
sin 62° = 0.88295
From the value of sin 62, equation (1) becomes
sin 62° = cos R
0.88295 = cos R
R = 
0.88295
R = 27.9997
≅ 28°
R = 28°
Step:2
Check for solution,
From equation 1,
sin 62° = cos R
Substitute R = 28°,
sin 62° = cos 28°
0.88295 = 0.88295
Result:
The value of R is 28° (Degrees), if the equation sin 62° = cos R true when 0° < R < 60°.
Answer:
Probability of not drawing a larger hammer: 17/20 Very likely
Probability of drawing a pair of 6 inch pliers: 5/40 Unlikely and 17/20 Very likely or 22/60 Unlikely
Probability of drawing 6 inch pliers from second basket: 0/20 Impossible, there aren't any pliers in the second basket, only hammers
Probability of drawing 6 inch pliers: 5/40 Unlikely
Step-by-step explanation:
