Answer:
identify materials to create a prototype
Answer:
Purpose - To paurswade the board to change the conditions of the locker room
Topic - Locker room condition
Method - Electronic Slideshow
Audience - School Board
Answer:
The answer is "Not all electronic health records can generate quality reports"
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Explanation:
The main objective of QI is to improve results, that uses the CDC to identifies improvement as just an aspect of the three-pronged service delivery scheme. It uses information for decision-making to improve strategies, initiatives, and outcomes, and other option can be described as follows:
- It the technology, which is fast enough.
- In this technology vendors are interested.
- In this, all the program does not require wireless networks.
Answer:
The answer is "Option A".
Explanation:
In the given code an integer array "x" is defined, that stores some elements and another integer variable "a" is declared, that holds a value that is "10". In this code a conditional statement is defined, which checks array element value, in if block element of array that position is 2 is greater then the element of array that position is 5.if this condition is true, so variable a value is change that is equal to 5. In else block if the above condition is not true so the value of a variable is equal to 8, and another options is wrong that can be described as follows:
- In option B, The given condition is not false, that's why it is not correct.
- In option C, The value of variable a is changed when condition is true or false, that's why it is not correct.
- In option D, It is wrong because we can compare array elements.
Big-O notation is a way to describe a function that represents the n amount of times a program/function needs to be executed.
(I'm assuming that := is a typo and you mean just =, by the way)
In your case, you have two loops, nested within each other, and both loop to n (inclusive, meaning, that you loop for when i or j is equal to n), and both loops iterate by 1 each loop.
This means that both loops will therefore execute an n amount of times. Now, if the loops were NOT nested, our big-O would be O(2n), because 2 loops would run an n amount of times.
HOWEVER, since the j-loop is nested within i-loop, the j-loop executes every time the i-loop <span>ITERATES.
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As previously mentioned, for every i-loop, there would be an n amount of executions. So if the i-loop is called an n amount of times by the j loop (which executes n times), the big-O notation would be O(n*n), or O(n^2).
(tl;dr) In basic, it is O(n^2) because the loops are nested, meaning that the i-loop would be called n times, and for each iteration, it would call the j-loop n times, resulting in n*n runs.
A way to verify this is to write and test program the above. I sometimes find it easier to wrap my head around concepts after testing them myself.
