You are standing 40 meters from the base of a tree that leans 8o away from you. The angle of elevation from you to the top of th
e tree is 20o. Find the slant height of the tree.
1 answer:
Answer:
the height of the tree is <em>15.49 m</em>
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Step-by-step explanation:
Step 1:
From the figure, we can determine ∠ATB by using the fact that the sum of all the angles in a triangle add up to 180°:
∠ ATB = 180° - 98° - 20°
∠ ATB = 62°
Step 2:
Therefore, using the law of sines, we can determine the height of the tree.
TB / sin(20°) = 40 / sin(62°)
TB = 40 × (sin(20°) / sin(62°))
<em>TB = 15.49 m </em>
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Therefore, the height of the tree is <em>15.49 m</em>
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Answer:
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Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 2, - 6) and (x₂, y₂ ) = (2, - 3) ← 2 points on the line
m = =
, thus
y = x + c ← is the partial equation
To find c substitute either ot the 2 points into the partial equation
Using (2, - 3), then
- 3 = + c ⇒ c = - 3 -
= -
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← equation of line