Answer:
![2^{-1}](https://tex.z-dn.net/?f=2%5E%7B-1%7D)
Explanation:
05/10
Simplifying
1/2
or 2^-1
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8 can't be square rooted as an integer. Therefore the answer can only result in a being a decimal, in double brackets or it can be a trick question.
Answer:
Step-by-step explanation:
- 2·
+ 20 = 32 - 2·
= 12
= 6- (v + 4) log 4 = log 6
- v + 4 = log 6 / log 4
- v + 4 = 1.29 (<em>rounded</em>)
- v = 1.29 - 4
- v = - 2.71
Divide 4/2 so you get 2= n over 4 then multiply 2 by 4 and then multiply n over 4 by 4 you’ll get 4*2=n, multiply 4 and 2.
n=8
Let
![f(x)=-2x^3+14x^2+24x+20](https://tex.z-dn.net/?f=f%28x%29%3D-2x%5E3%2B14x%5E2%2B24x%2B20)
. You have
![f(5)=240](https://tex.z-dn.net/?f=f%285%29%3D240)
, which means - by the polynomial remainder theorem - that the remainder upon dividing
![f(x)](https://tex.z-dn.net/?f=f%28x%29)
by
![x-5](https://tex.z-dn.net/?f=x-5)
is 240, and so
![x-5](https://tex.z-dn.net/?f=x-5)
is not a factor of
![f(x)](https://tex.z-dn.net/?f=f%28x%29)
.