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kotykmax [81]
2 years ago
6

Solve for the unknown.​

Mathematics
1 answer:
natka813 [3]2 years ago
5 0
Divide 4/2 so you get 2= n over 4 then multiply 2 by 4 and then multiply n over 4 by 4 you’ll get 4*2=n, multiply 4 and 2.

n=8
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6. Choose the step to take to solve this equation for x.
DanielleElmas [232]

Answer:

add 7 to the right!

X=8+7

X=15

5 0
2 years ago
Read 2 more answers
How many years is 694.44 days?
antoniya [11.8K]

Answer:

1.9 years

Step-by-step explanation:

There are 365 days in a year

694.44 / 365 = 1.9

Hope this helps!

6 0
2 years ago
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In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the
earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

<em>C</em> = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events <em>A</em>, <em>B</em> and <em>C</em> are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

7 0
2 years ago
Draw Three triangles One equilateral one isosceles and one scalene label Each and explain how you classified each triangle
Fantom [35]
Here is a picture of each.

Here are the definitions of each:
1. Equilateral- this triangle has side lengths that are all the same (congruent).
2. Isosceles-this triangle has exactly 2 sides that are the same length(congruent).
3. Scalene- this triangle has no sides that are the same length.

8 0
3 years ago
Quick math question ghghghujhghj
yawa3891 [41]

\text{Hey there!}

\bf{3(4x + 1) - (5x + 7)}

\text{FIRST: distribute the NEGATIVE sign}\text{(On the RIGHT side of the problem/equation)}

\bf{-1 (5x + 7)}

\bf{-1(5x) + -1(7)}

\bf{-1(5x) = -5x}

\bf{-1(7) = -7}

\bf{\underline{= -5x - 7}}

\text{SECOND: distribute the LEFT side of the problem/equation}

\bf{3(4x+1)}

\bf{3(4x) + 3(1)}

\bf{3(4x) = 12x}

\bf{3(1) = 3}

\bf{\underline{12x+3}}

\text{THIRD: make the new equation}

\text{Equation becomes: \bf{12x + 3 - 5x - 7}}

\text{FOURTH: COMBINE your like terms}

\bf{(12x - 5x) + (3 - 7)}

\bf{12x  - 5x  = 7x}

\bf{3 - 7 = -4}

\text{ANSWER}

\boxed{\text{Thus, your answer is: \boxed{\huge\text{\bf7x - 4}}}}}\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

3 0
3 years ago
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