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3 years ago

Solve for the unknown.

Mathematics

1 answer:

natka813 [3]3 years ago

5 0

Divide 4/2 so you get 2= n over 4 then multiply 2 by 4 and then multiply n over 4 by 4 you’ll get 4*2=n, multiply 4 and 2.

n=8

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Is 1/a rational or irrational

Alenkinab [10]

The number 1 can be classified as: a natural number, a whole number, a perfect square, a perfect cube, an integer. This is only possible because 1 is a RATIONAL number

6 0

2 years ago

Help im lost a b c or d

Marrrta [24]

Answer:

Step-by-step explanation:

Angle FEG and angle DEF are supplementary (They both form a 180 degree angle) so you can conclude:

180 = 119 + angleFEG

angleFEG = 61 degrees

Angle HEG and DEF are vertical angles so you can conclude:

angleHEG = angleDEF

andgleHEG = 119

5 0

3 years ago

Read 2 more answers

Product 1,370 m , 31.7 s

LenaWriter [7]

2605740 sec is the answer to this because you turn the min to sec and time them then you get the answer

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3 years ago

NEED HELP WILL MARK BRAINLEST

Marina CMI [18]

Answer:

103.27 degree

Step-by-step explanation:

You need to find the angle of the interior of the triangle first, and then find the exterior. Hope I helped!

3 0

2 years ago

Auggie spent all of his money in 5 stores. In each store, he spent $1 more than one-half of what he had when he went in. How man

Rus_ich [418]

Answer:

Total amount of Auggle when he entered the first = $62

Step-by-step explanation:

Let x be the total amount of Auggle when he entered the first.

Number of the store = 5

We need to find the total amount of Auggle when he entered the first.

Solution:

From the above statement he spent $1 more than one-half of total amount of Auggle when he entered the first.

⇒ $\frac{x}{2}+1$

⇒ $\frac{x+2}{2}$

So, when he leaves the first store

⇒ $x-\frac{x+2}{2}$

⇒ $\frac{2x-x-2}{2}$

⇒ $\frac{x-2}{2}$

When he go second store, he spends $\frac{x-2}{2\times 2}+1$

So, he has ⇒ $\frac{x-2}{4}-1$

⇒ $\frac{x-2-4}{4}$

⇒ $\frac{x-6}{4}$

Similarly for third store.

⇒ $\frac{x-6}{4\times 2} -1$

⇒ $\frac{x-6-8}{8}$

⇒ $\frac{x-14}{8}$

Similarly for fourth store.

⇒ $\frac{x-14}{8\times 2} -1$

⇒ $\frac{x-14-16}{16}$

⇒ $\frac{x-30}{16}$

Similarly for fifth store.

⇒ $\frac{x-30}{16\times 2} -1$

⇒ $\frac{x-30-32}{32}$

⇒ $\frac{x-62}{32}$

When he leaves the fifth store, he has $\frac{x-62}{32}=0$

⇒ $x-62=0$

$x = \$62$

Therefore, Auggie have $62 when he entered the first store.

4 0

3 years ago

Solve for the unknown.​

Solve for the unknown.