18. If f(x)=[xsin πx] {where [x] denotes greatest integer function}, then f(x) is:
since x denotes the greatest integers which could the negative or the positive values, also x has a domain of all real numbers, and has no discontinuous point, then x is continuous in (-1,0).
Answer: B]
20. Given that g(x)=1/(x^2+x-1) and f(x)=1/(x-3), then to evaluate the discontinuous point in g(f(x)) we consider the denominator of g(x) and f(x). g(x) has no discontinuous point while f(x) is continuous at all points but x=3. Hence we shall say that g(f(x)) will also be discontinuous at x=3. Hence the answer is:
C] 3
21. Given that f(x)=[tan² x] where [.] is greatest integer function, from this we can see that tan x is continuous at all points apart from the point 180x+90, where x=0,1,2,3....
This implies that since some points are not continuous, then the limit does not exist.
Answer is:
A]
Answer:
Lenthg times width
Step-by-step explanation:
Option C:
x = 30
Solution:
The given image is a triangle.
angle 1, angle 2 and angle 3 are interior angles of a triangle.
angle 4 is the exterior angle of a triangle.
m∠4 = 2x°, 
, m∠3 = 20°
Exterior angle theorem:
<em>In triangle, the measure of exterior angle is equal to the sum of the opposite interior angles.</em>
By this theorem,
m∠4 = m∠2 + m∠3
Subtract 
on both sides of the equation.
To make the denominator same and then subtract.
Multiply by 
on both sides of the equation.
x° = 30°
x = 30
Hence option C is the correct answer.
Answer:
y = -5
Step-by-step explanation:
Isolate y:
-3x + 9y = -57
9y = -57 + 3x
y = (-57/9) + (3/9)x
Substitute for x:
y = (-57/9) + (3/9)(4)
y = (-57/9) + (12/9)
y = (-45/9)
y = -5
