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3 years ago

6

Hendrick wants to enlarge a photo that is 4 inches wide and 6 inches tall. The enlarged photo keeps the same ratio. How large is

the enlarged photo if it is 12 inches wide

1 answer:

lukranit [14]3 years ago

4 0

The photo would be 18 inches tall.

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Three quarter of the students running a 100-yard race finished with an average time of 16 seconds. The remaining 25% of students

iren [92.7K]

Answer:

15 seconds

Step-by-step explanation:

Because the split id 25% and 75%, we could create another average pretending that there are four kids, one who ran in 12 seconds, and three who ran in 16.

Equation for averages: (a₁ + a₂ + a₃ + ... $a_{n}$ )/ n

Plug in:<em> (12 + 16 + 16 + 16)/4</em>

Add: 60/4

Divide: 15 seconds

5 0

3 years ago

Find the missing side length to the nearest tenth of a millimeter.

wel

Answer:

17.9

Step-by-step explanation:

3.7²+17.5²=319.94

$\sqrt{319.94\\$ = 17.9

8 0

3 years ago

Audrey deposited $40,000 in a savings account with simple interest. Five years later, she had earned $30,000 in interest. What w

Fittoniya [83]

$~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill&\$30000\\ P=\textit{original amount deposited}\dotfill & \$40000\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &5 \end{cases} \\\\\\ 30000=(40000)(\stackrel{\%}{\frac{r}{100}})(5)\implies \cfrac{30000}{(40000)(5)}=\cfrac{r}{100}\implies \cfrac{3}{20}=\cfrac{r}{100} \\\\\\ \cfrac{300}{20}=r\implies \stackrel{\%}{15}=r$

4 0

2 years ago

Choose the solution(s) of the following system of equations x2 + y2 = 6 x2 – y = 6

ElenaW [278]

<h2>Answer</h2>

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

Or as ordered pairs: $(\sqrt{6} ,0),(-\sqrt{6} ,0),(\sqrt{5} ,-1),(-\sqrt{5} ,-1)$

<h2>Explanation</h2>

Lets solve our system of equations step by step

$x^2+y^2=6$ equation (1)

$x^2-y=6$ equation (2)

1. Solve for $x^2$ in equation (2)

$x^2-y=6$

$x^2=6+y$ equation (3)

2. Replace equation (3) in equation (1) and solve for $y$

$x^2+y^2=6$

$6+y+y^2=6$

$y^2+y=0$

$y(y+1)=0$

$y=0$ or $y=-1$

3. Replace the values of $y$ in equation (3) and solve for $x$

- For $y=0$

$x^2=6+y$

$x^2=6$

$x=\sqrt{6}$ or $x=-\sqrt{6}$

- For $y=-1$

$x^2=6+y$

$x^2=6-1$

$x^2=5$

$x=\sqrt{5}$ or $x=-\sqrt{5}$

So, the solutions of our system of equation are:

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

6 0

3 years ago

Read 2 more answers

What is the value of x in the equation 1.5(x + 4) – 3 = 4.5(x – 2)?

rjkz [21]

Hello!

Step 1: Simplify both sides of the equation.<span><span><span>
1.5<span>(<span>x+4</span>)</span></span>−3</span>=<span>4.5<span>(<span>x−2</span>)</span></span></span><span><span><span><span><span><span>

(1.5)</span><span>(x)</span></span>+<span><span>(1.5)</span><span>(4)</span></span></span>+</span>−3</span>=<span><span><span>(4.5)</span><span>(x)</span></span>+<span><span>(4.5)</span><span>(<span>−2</span>)</span></span></span></span>(Distribute)<span><span><span><span><span>

1.5x</span>+6</span>+</span>−3</span>=<span><span><span>4.5x</span>+</span>−9</span></span><span><span><span>

(<span>1.5x</span>)</span>+<span>(<span>6+<span>−3</span></span>)</span></span>=<span><span>4.5x</span>−9</span></span>(Combine Like Terms)<span><span><span>

1.5x</span>+3</span>=<span><span>4.5x</span>−9</span></span><span><span><span>
</span></span></span>Step 2: Subtract 4.5x from both sides.<span><span><span><span>

1.5x</span>+3</span>−<span>4.5x</span></span>=<span><span><span>4.5x</span>−9</span>−<span>4.5x</span></span></span><span><span><span>

−<span>3x</span></span>+3</span>=<span>−9</span></span>

Step 3: Subtract 3 from both sides.<span><span><span><span>

−<span>3x</span></span>+3</span>−3</span>=<span><span>−9</span>−3</span></span><span><span>

−<span>3x</span></span>=<span>−12</span></span>

Step 4: Divide both sides by -3.<span><span><span>

−<span>3x</span></span><span>−3</span></span>=<span><span>−12</span><span>−3</span></span></span><span>

x=<span>4

Hope this helps! Cheerio, and have a lovely day!</span></span>

7 0

3 years ago

Read 2 more answers