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3 years ago

A potential threat to administrators’ ability to manage the correctional system is

Computers and Technology

1 answer:

OlgaM077 [116]3 years ago

4 0

(privatization) is your answer to this question you are asking

You might be interested in

A group of N stations share a 56-kbps pure ALOHA channel. Each station outputs a 1000-bit frame on average once every 100 sec, e

Sunny_sXe [5.5K]

Explanation:

Here, in the given statement, maximum flow capacity of the ALOHA channel = 18.4% = 0.184

Then, the stations N share 56 kbps

And, the channel rate = $0.184*56$ $= 10.304 kbps.$

Then, the outputs of the wach stations is $1000-bit frames/100 sec$

$\therefore$ , the output of the bits/ sec by each stations = $\frac{1000}{100} bits/sec = 10 bits/sec$

So, The output of the N stations is 10 bits/sec on the channel that having $10.304kb/sec$

Finally, N = $\frac{(10.304 \times 10^{3})}{10} = 1030 stations$

3 0

3 years ago

Jordan likes to use his smartphone in his car. He uses it as a navigation device and connects it via Bluetooth to listen to musi

Levart [38]

Answer:

I think A Bluetooth receiver is causing the smartphone to over heat

8 0

2 years ago

What was designed as an area where computer vendors could store data that is shielded from user activities and operating system

Nataliya [291]

Answer:

host protected area

Explanation:

7 0

2 years ago

You have a group of friends coming to visit you for your high school reunion, and you want to take them out to eat at a local re

-BARSIC- [3]

Answer:

Python code is explained below

Explanation:

def RestaurentSelector():

#stroring the restaurants data

restaurents=[["Joe's Gourmet Burgers","no","no","yes"],["Main Street Pizza Company","yes","yes","yes"],["Corner Cafe","yes","no","yes"],["Mama's Fine Italian","yes","no","no"],["The Che'fs Kitchen","yes","yes","yes"]]

#taking the requirements for party

isVeg=input("Is anyone at your party a vegetarian? ")

isVegan=input("Is anyone at your party a vegan? ")

isGF=input("Is anyone at your party a gluten-free? ")

#printing the info

print("Hera are your restaurant choices :")

#loop to check each restaurent

for x in restaurents:

#checking for veg requirement

if isVeg=="yes" and x[1]=="no":

#skipping the current restaurent if is satisfying

continue

#checking for vegan requirement

if isVegan=="yes" and x[2]=="no":

#skipping the current restaurent if is satisfying

continue

#checking for glutan free requirement

if isGF=="yes" and x[3]=="no":

#skipping the current restaurent if is satisfying

continue

#if all requirementws are satisfied

#printing the restaurent name

print("\t",x[0])

#exiting the function\

#calling the function

RestaurentSelector()

4 0

3 years ago

The template code provided is intended to take two inputs, x and y, from the user and print "pass" if one or more of the followi

just olya [345]

import java.util.Scanner;

public class U3_L6_Activity_Two{

public static void main(String[] args){

Scanner scan = new Scanner(System.in);

int x = scan.nextInt();

int y = scan.nextInt();

if(x>=4|| ((y < 5) && ((x+y) < 7))){

System.out.println("pass");

}

I'm pretty sure this is what you're looking for. Best of luck.

7 0

3 years ago