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2 years ago

Year 1 number sold 725

Mathematics

1 answer:

Ivan2 years ago

8 0

Answer:

2, 240

Step-by-step explanation:

In the table, the values should be

Year 1 725

Year 2 579

Year 3 696

Since Year 4 sold 112% of the previous 3 years combined, we add 725+579+696=2000. We can find 112% by writing a proportion.

$\frac{112}{100} =\frac{x}{2000}$

We solve through cross multiplication of numerator and denominator of the opposite fraction.

$112(2000)=100(x)\\224000=100x\\2,240=x$

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If the midpoint of (4, 3) and point A has coordinates (-2, 6), what are the coordinates of point B?

baherus [9]

(xA+xB)/2, (yA+yB)/2 = (4,3)
(xA+xB)/2 = 4
(-2+xB) = 8 --> xB = 8+2 --> xB = 10
(yA+yB)/2 = 3
(6+yB) = 6 --> yB = 6-6 --> yB = 0

B = (10,0)

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2 years ago

Find the area of each figure. Round to the nearest tenth if necessary.

natita [175]

Answer:

Solution given:

diameter(d)=6mm

base(b)=8mm

height (h)=5mm

Area of figure=area of parallelogram +area of semi circle

base*height+½π(d/2)²
8*5+½*π×(6/2)²
40+14.14
54.4mm²
Area :54.14mm²

for triangle

base[b]=6ft

height(h)=9ft

for square

length[l]=9ft

Area of figure=area of square +area of triangle

=l²+½*b*h
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=81+27
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Area: 108ft²

6 0

2 years ago

What is the product of (x 1)^2?

Viktor [21]

The product of (x1)^2 is 20

6 0

3 years ago

40% of Oatypop cereal boxes contain a prize. Hannah plans to keep buying cereal until she gets a prize. What is the probability

aleksley [76]

Answer:

$(0.6)^{n}+n(0.4)(0.6)^{n-1}+\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}$

Step-by-step explanation:

We will use the binomial distribution. Let X be the random variable representing the no. of boxes Hannah buys before betting a prize.

Our success is winning the prize, p =40/100 = 0.4

Then failure q = 1-0.4 = 0.6

Hannah keeps buying cereal boxes until she gets a prize. Then n be no. times she buys the boxes.

P(X ≤ 3) = P(X=0) +P(X=1)+P(X=2)+P(X=3)

= $\binom{n}{0}p^{0}q^{n-0}$ + $\binom{n}{1}p^{1}q^{n-1}$ + $\binom{n}{2}p^{2}q^{n-2}$ + $\binom{n}{3}p^{3}q^{n-3}$

= $q^{n}+npq^{n-1}$ + $\frac{n(n-1)(p)^{2}q^{n-2}}{2}$ + $\frac{n(n-1)(n-2)p^{3}q^{n-3}}{6}$

= $(0.6)^{n}+n(0.4)(0.6)^{n-1}+[tex]\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}$

7 0

2 years ago

Read 2 more answers

Alex, Stephen and Bridget share some sweets in the ratio 4:1:1. Alex gets 36 sweets. How many sweets are there altogether?

STALIN [3.7K]

Answer:

There are 54 total sweets

Step-by-step explanation:

Alex: Stephen : Bridget : total

4: 1 : 1 : 4+1+1 = 6

Alex gets 36

36/4 = 9

Multiply each number by 9

Alex: Stephen : Bridget : total

4*9: 1*9 : 1*9 : 6*9

36: 9 : 9 : 54

There are 54 total sweets

4 0

3 years ago

Read 2 more answers