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Dmitrij [34]
3 years ago
13

NO LINKS PLEASE I ACTUALLY NEED HELP THEY'RE 2 PARTS

Mathematics
1 answer:
eimsori [14]3 years ago
3 0
I’m on the same question
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Evaluate using the trigonometric ratios Tan 60° + Cos 30° sin 60° + Cot 30° /CSC 30° Sec 30°<br>​
algol13

Answer:

(24 + 3√3) / 16.

Step-by-step explanation:

Tan 60° + Cos 30° sin 60° + Cot 30 /  csc 30 sec 30

= √3 + √3/2 * √3/2 + √3 /   2 * 2/√3

= 2√3 + 3/4 / 4/√3

= (8√3 + 3)/ 4 / √3

= 24 + 3√3 / 16

5 0
2 years ago
This was the question it got deleted I just need 1,2,5
scoundrel [369]

Answer:

1. The volume of the cylinder is 263 cm^{3}.

2. The volume of the cylinder is 12 m^{3}.

3. The volume of the cylinder is 3165.1 cm^{3}.

4. The radius of the cylinder is 3.6 cm.

5a. Area of the base is 50.2 cm^{2}.

5b. The curved surface area of the pencil holder is 351.7 cm^{2}.

5c. The surface are of the pencil holder is 452.2 cm^{2}.

Step-by-step explanation:

1. The given shape is a cylinder, so that;

volume of a cylinder = \pir^{2}h

                                  = 3.14 x (3.8)^{2} x 5.8

                                  = 262.98128

The volume of the cylinder is 263 cm^{3}.

2. This is also a cylinder, but with a given diameter.

radius = \frac{diameter}{2}

          = \frac{1.2}{2} = 0.6 m

volume of a cylinder = \pir^{2}h

                                  = 3.14 x (0.6)^{2} x 10.6

                                  = 11.98224

The volume of the cylinder is 12 m^{3}.

3. volume of a cylinder = \pir^{2}h

                                      = 3.14 x 6^{2} x 28

                                      = 3165.12

The volume of the cylinder is 3165.1 cm^{3}.

4. volume of a cylinder = \pir^{2}h

239 = 3.14 x r^{2} x 6

239 = 18.84 r^{2}

r^{2} = \frac{239}{18.84}

   = 12.6858

r = \sqrt{12.6858}

 = 3.5617

The radius of the cylinder is 3.6 cm.

5. Area of the base = \pir^{2}

radius = \frac{diameter}{2}

           = \frac{8}{2} = 4 cm

Area of the base = 3.14 x 4^{2}

                            = 50.24

Area of the base is 50.2 cm^{2}.

5b. Area of the curved surface of the pencil holder = 2\pirh

                                                                    = 2 x 3.14 x 4 x 14

                                                                     = 351.68

The curved surface area of the pencil holder is 351.7 cm^{2}.

5c. Surface area of the pencil holder = 2\pirh + 2\pir^{2}

                               = 2\pir(h + r)

                                = 2 x 3.14 x 4 (14 + 4)

                                = 452.16

The surface are of the pencil holder is 452.2 cm^{2}.

7 0
3 years ago
Using substitution how do u solve <br> 3y+2x=6<br> and 5y-2x=10
Sergeu [11.5K]
<span>3y+2x=6
5y-2x=10
--------------add
8y = 16
y = 2

</span>3y+2x=6
3(2)+2x=6
6 + 2x = 6
2x = 0
x = 0

answer: x = 0 and y = 2 or (0,2)
7 0
3 years ago
Read 2 more answers
Choose one. Statistics are A) Measures of populations; B) Always estimations; C) Notated with small Roman letters; D) (b) and (c
DanielleElmas [232]
D is the answer
hope it helps
7 0
3 years ago
What would the answer be to this
Vladimir79 [104]

Answer:

265.2

Step-by-step explanation:

3(6*13)=234

2*15.6=31.2

234+31.2=265.2

6 0
3 years ago
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