1. Let x = # 2. "Five less than six times a number" can be written as: 6x - 5 3. "is at least" is the same as "greater than or equal to" and can be written as: >= 4. "nine subtracted from two times that number" can be written as: 2x - 9 5. the equation is: 6x - 5 >= 2x - 9 6. solve for x by grouping the x variable terms on one side and the constants on the other side: 6x - 5 >= 2x - 9 -2x +5 -2X +5 4x >= -4 7. divide each side by 4, and you get: x = -1