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Julli [10]
4 years ago
12

Four more than six times a number is at least 40. Find the possible range of values.

Mathematics
1 answer:
Setler [38]4 years ago
5 0
1. Let x = #
2. "Five less than six times a number" can be written as: 6x - 5
3. "is at least" is the same as "greater than or equal to" and can be written as: >=
4. "nine subtracted from two times that number" can be written as: 2x - 9
5. the equation is: 6x - 5 >= 2x - 9
6. solve for x by grouping the x variable terms on one side and the constants on the other side:
6x - 5 >= 2x - 9
-2x +5 -2X +5
4x >= -4
7. divide each side by 4, and you get: x = -1
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Please answer with explanation
nalin [4]

Answer:

(a)- 2 [ ( - \frac { 1 } { 4 } ) - 12 ( - 1 ) ^ { 2 } ] - 5 [ 24 + 2 ( - 12 ) ] ^ { 2 }−2[(−

4

1

)−12(−1)

2

]−5[24+2(−12)]

2

Do the arithmetic.

Calculate -1−1 to the power of 22 and get 11.

-2\left(-\frac{1}{4}-12\right)-5\left(24+2\left(-12\right)\right)^{2}−2(−

4

1

−12)−5(24+2(−12))

2

Subtract one term from another.

Subtract 1212 from -\frac{1}{4}−

4

1

to get -\frac{49}{4}−

4

49

.

-2\left(-\frac{49}{4}\right)-5\left(24+2\left(-12\right)\right)^{2}−2(−

4

49

)−5(24+2(−12))

2

Multiply two factors together.

Multiply -2−2 and -\frac{49}{4}−

4

49

to get \frac{49}{2}

2

49

.

\frac{49}{2}-5\left(24+2\left(-12\right)\right)^{2}

2

49

−5(24+2(−12))

2

Multiply two factors together.

Multiply 22 and -12−12 to get -24−24.

\frac{49}{2}-5\left(24-24\right)^{2}

2

49

−5(24−24)

2

Subtract one term from another.

Subtract 2424 from 2424 to get 00.

\frac{49}{2}-5\times 0^{2}

2

49

−5×0

2

Multiply two factors together.

Multiply 55 and 00 to get 00.

\frac{49}{2}-0

2

49

−0

Add two terms together.

Subtract 00 from \frac{49}{2}

2

49

to get \frac{49}{2}

2

49

.

\frac{49}{2}

2

49

2

49

=24.5

(b)−a

2

b

2

−3a

3

b

2

a=−

3

1

b=−1

Step-by-step explanation:

Hope it helps u

FOLLOW MY ACCOUNT PLS PLS

3 0
3 years ago
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