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fomenos
3 years ago
10

Please Solve ASAP

Mathematics
1 answer:
maxonik [38]3 years ago
7 0

Step-by-step explanation:

If x = −1, then y =-2

If x = 0, then y =1

If x = 1, then y =4

If x = 2, then y =7

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Please try and solve it
astraxan [27]
This answer would be y=5
7 0
3 years ago
$30 before tax <br> discount 20% tax 6.4% <br> tip 15%
jeyben [28]

Answer: $30.44

Step-by-step explanation:

$30 20% of tht is 6

30-6=24

tax is 6.4% which is 1.94

24+1.94 which equals $25.94

tips is 15% 4.5 so we add that to $25.94

 so total is $30.44

4 0
3 years ago
Read 2 more answers
Which graph matches the equation y+3=2(x+3)?
Vlad1618 [11]

Answer:

The graph that includes points (-3,-3) and (0,3)

Step-by-step explanation:

In the pictures attached, the options are shown.

The equation:

y+3=2(x+3)

has the point-slope form, which is:

y-y₁=m(x-x₁)

where (x₁, y₁) is a point on the line and <em>m</em> is its slope. This means that (-3,-3) is on the line. To know the y-intercept of the line, we have to replace x = 0 into the equation, as follows:

y+3=2(0+3)

y+3 = 6

y = 6 - 3

y = 3

Then, point (0, 3) is on the line.

8 0
3 years ago
Help Eveaultaint the question
svet-max [94.6K]
10-x+y÷2
10-(5)+(2)÷2
10-5+2÷2
7÷2
3.5???
I'm pretty sure that's correct, I'm sorry if it's wrong though
5 0
3 years ago
Police estimate that​ 25% of drivers drive without their seat belts. If they stop 6 drivers at​ random, find the probability tha
Furkat [3]

Answer:

17.80% probability that all of them are wearing their seat belts.

Step-by-step explanation:

For each driver stopped, there are only two possible outcomes. Either they are wearing their seatbelts, or they are not. The drivers are chosen at random, which mean that the probability of a driver wearing their seatbelts is independent from other drivers. So we use the normal probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Police estimate that​ 25% of drivers drive without their seat belts.

This means that 75% wear their seatbelts, so p = 0.75

If they stop 6 drivers at​ random, find the probability that all of them are wearing their seat belts.

This is P(X = 6).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{6,6}.(0.75)^{6}.(0.25)^{0} = 0.1780

17.80% probability that all of them are wearing their seat belts.

3 0
3 years ago
Read 2 more answers
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