Answer:
Perimeter of quadrilateral = 12.35 units
Explanation:
To find - Find the perimeter of a quadrilateral with vertices at C (−2, 4), D (−3, 1), E (1, 0), and F (−1, 2).
Proof -
The figure becomes :
We have the points -
C (−2, 4),
D (−3, 1),
E (1, 0),
F (−1, 2)
Now,
We know that -
The perimeter = Distance of (CD + DE + EF + FC)
Now,
Distance of CD = √(-3 + 2)² + (1 - 4)²
= √(-1)² + (-3)²
= √1 + 9
= √10 = 3.16
⇒Distance of CD = 3.16
Now,
Distance of DE = √(1 + 3)² + (0 - 1)²
= √(4)² + (-1)²
= √16 + 1
= √17 = 4.12
⇒Distance of DE = 4.12
Now,
Distance of EF = √(-1 - 1)² + (2 - 0)²
= √(-2)² + (2)²
= √4 + 4
= √8 = 2.83
⇒Distance of EF = 2.83
Now,
Distance of FC = √(-2 + 1)² + (4 - 2)²
= √(-1)² + (2)²
= √1 + 4
= √5 = 2.24
⇒Distance of FC = 2.24
So,
Perimeter of quadrilateral = 3.16 + 4.12 + 2.83 + 2.24
= 12.35 units
⇒Perimeter of quadrilateral = 12.35 units
That statement is true
an HR Diagram would plotted the absolute magnitude of the stars against their color. The resultant plots of this diagram showed that the relationship between the luminosity and temperature of the Star are not Random
Explanation:
To extend those records, paleoclimatologists look for clues in Earth's natural environmental records. Clues about the past climate are buried in sediments at the bottom of the oceans, locked away in coral reefs, frozen in glaciers and ice caps, and preserved in the rings of trees.
Answer:
b. Since king snakes with these markings were avoided by predators, they were able to survive to pass on this trait to offspring.
Explanation:
The conditions that resulted in a large population of king snakes with these types of markings is that since king snakes with these markings were avoided by predators, they were able to survive to pass on this trait to offspring.