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3 years ago

Charlie runs at a speed of 3 yards per second. About how many miles per hour does Charlie run

2 answers:

7 0

To find the answer, you first must find how many yards Charlie can run in a minute. Since there are 60 seconds in a minute, you multiply 3 times 60, which is 180. Then you must multiply this number by 60 again, because there are 60 minutes in an hour. This equals 10,800, your answer.

Charlie can run 10,800 yards in an hour.

Law Incorporation [45]3 years ago

5 0

The answer is 6.1 miles

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Solve the system. If there is more than one solution, write the general solution. x + y - 2z = 9 3x + y + 2z = 15 x - 5y + 22z =

Margaret [11]

Answer:

Step-by-step explanation:

Given the system of equation

x + y - 2z = 9 ... 1

3x + y + 2z = 15 ...2

x - 5y + 22z = -27... 3

First let us reduce the system of equation into two with two unknowns.

Subtracting 1 from 3

y-(-5y) + (-2z-22z) = 9-(-27)

y+5y + (-24z) = 9+27

6y-24z = 36 ... 4

Multiplying equation 1 by 3 and subtracting from equation 2

3x + 3y - 6z = 27

3x + y + 2z = 15

On subtracting both;

(3y-y)+(-6z-2z) = 27-15

2y-8z = 12 ... 5

Equating 4 and 5

6y-24z = 36 ... 4

2y-8z = 12 ... 5

Multiplying equation 5 by 3 the equation becomes;

6y-24z = 36 ... 6

6y-24z = 36 ... 7

We can see that equation 6 and 7 are the same;

let y = k

6k - 24z = 36

k - 4z = 6

4z = k-6

z = k-6/4

Substituting y = k and z = k-6/4 into equation 1 to get x

From 1; x + y - 2z = 9 ... 1

x + k -2( k-6/4) = 9

x + k - (k-6)/2 = 9

x = 9+(k-6)/2-k

x = {18+(k-6)-2k}/2

x = (12-k)/2

The solutions to the system of equations are x = (12-k)/2, y = k, z = (k-6)/4 where k is any constant. This shows that the system of equation has infinite solutions.

7 0

3 years ago

If I have to move the constant over to one side, what value would I have to add to the left side in order to complete the square

trapecia [35]

Answer:

To make the equation complete square , we have to add 11 .

Step-by-step explanation:

Given as :

The linear equation is

x² + 4 x - 5 = 2

Now, move the constant to left side of equation

So, x² + 4 x - 5 - 2 = 0

Or, x² + 4 x - 7 = 0

<u>Now, to make equation complete square , let add 11 both side</u>

So, x² + 4 x - 7 + 11 = 11

Or, x² + 4 x + 4 = 11

Now, applying mid-term break

So, x² + 2 x + 2 x + 4 = 11

Or, x ( x + 2) + 2 (x + 2) = 11

Or, (x + 2) ( x + 2) = 11

Or, (x + 2)² = 11

Hence, To make the equation complete square , we have to add 11 . Answer

6 0

3 years ago

Find the perimeter of the rectangle with points...<br> W(6,9), X(9,7), Y(3,-2), Z(0,0)

Svetradugi [14.3K]

Find the perimeter of the rectangle with points...
W(6,9), X(9,7), Y(3,-2), Z(0,0)

5 0

3 years ago

Find the nonpermissible replacement for y in this expression y-7/y+9

Vesnalui [34]

Answer:

y ≠ - 9

Step-by-step explanation:

the denominator of the expression cannot equal zero as this would make the expression undefined. Equating the denominator to zero and solving gives the value that y cannot be

solve y + 9 = 0 ⇒ y = - 9 ← not permissable

5 0

3 years ago

determine (a) the volume and (b) the surface area of the three-dimensional figure. when appropriate, use pi key on your calculat

lawyer [7]

Answer:

$Volume = 150 yd^3$

$Surface Area = 150 yd^2$

Step-by-step explanation:

Going by the dimensions of the given three-dimensional figure, we can conclude that the figure is that of a cube. The height, length and width are equal.

Volume of a cube is given as $a^3$ , while surface area of a cube is given as $6a^2$

Where, a = the side length = 5 yards

$Volume = a^3 = 5^3$

$Volume = 150 yd^3$

$Surface Area = 6a^2 = 6(5)^2$

$Surface Area = 150 yd^2$

3 0

4 years ago