Question

A circus tent is cylindrical up to a height of 4 m and conical above. If its

Answer 1

Answer:

Step-by-step explanation:

wait are you sure that the slant height is 40m... that would make this question impossible...

The bases are two circles = π$r^{2}$.

The rectangle is length x width. The length is the height h, and the width is the circumference of the base: 2πr. So, the rectangle is 2πrh.

The formula needed to get surface area of 4m and below is

π$r^{2}$ + 2πrh.

If the diameter is 105, the radius is 52.5.

The height is 4.

Substitute in numbers:

π$(52.5)^{2}$ + 2π(52.5)(4)

This is JUST THE CYLINDRICAL PART

The conical section's formula is πr(r+$\sqrt{h^{2} + r^{2} }$).

im sorry idk how to explain the formula but there's probably a formula derivation video somewhere, just search "cone surface area formula derivation"

Use the pythagorean theorem to find the height h. think you cut the cone in the middle, which gives you a triangle. The hypotenuse is the slant height, 40 m, and the base is the radius, 52.5 (here's where things get weird - if it's 40 idk what to tell you but if it isnt then just use pythagorean theorem with 52.5 and the slant height)

When you find the height, substitute in the values into the conical section surface area formula.

Add that to π$(52.5)^{2}$ + 2π(52.5)(4)

Thats the total area of canvas required.

Let me know if the slant height isn't 40... if it is im sorry :/