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notka56 [123]
3 years ago
7

How many faces does the figure have. A. 6 B. 4 C. 3 D. 5?

Mathematics
2 answers:
gogolik [260]3 years ago
4 0

Answer:

IS D

Step-by-step explanation:

Just took the quiz

ozzi3 years ago
3 0
D. 5 BECAUSE 3 SIDE FACES AND 2 FRONT FACES
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Question 3- Please help. Find the area of the sector for the image below:
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Answer:

The answer is 16.8 cm^ 2.

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3 years ago
According to the National Institute on Drug Abuse, a U.S. government agency, 17.3% of 8th graders in 2010 had used marijuana at
miskamm [114]

Answer:

The conditions for use of the normal model to represent the distribution of sample proportion are not met. He should increase the sample size until the conditions are met.

If the test is done anyway, the null hypothesis failed to be rejected.

The conclusion is taht there is not enough evidence to support the claim that the percentage is lower in this district.

Step-by-step explanation:

The conditions for use of the normal model to represent the distribution of sample proportion are not met, as the affirmative responses are less than 10.

np=80*0.1=8

If the test of hypothesis is done as if the conditiones were met, we know that the claim is that  the percentage is lower in this district.

Then, the null and alternative hypothesis are:

H_0: \pi=0.173\\\\H_a:\pi

The significance level is 0.05.

The sample has a size n=80.

The sample proportion is p=0.1.

 

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.173*0.827}{80}}\\\\\\ \sigma_p=\sqrt{0.001788}=0.042

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.1-0.173+0.5/80}{0.042}=\dfrac{-0.067}{0.042}=-1.578

This test is a left-tailed test, so the P-value for this test is calculated as:

P-value=P(z

As the P-value (0.057) is greater than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that  the percentage is lower in this district.

7 0
3 years ago
What do you add to 2 2/9 to make 4
shutvik [7]

Answer:

1 7/9

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
2. The dot plot shows samples of the number
tatuchka [14]

Answer:hi

Step-by-step explanation:hello

5 0
3 years ago
Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are sel
serious [3.7K]

Complete Questions:

Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are selected does not matter, from the positive integers not exceeding the given integers.

a. 40

b. 48

c. 56

d. 64

Answer:

a. 0.35

b. 0.43

c. 0.49

d. 0.54

Step-by-step explanation:

(a)

The objective is to find the probability of selecting none of the correct six integers from the positive integers not exceeding 40.  

Let s be the sample space of all integer not exceeding 40.

The total number of ways to select 6 numbers from 40 is |S| = C(40,6).

Let E be the event of selecting none of the correct six integers.

The total number of ways to select the 6 incorrect numbers from 34 numbers is:

|E| = C(34,6)

Thus, the probability of selecting none of the correct six integers, when the order in which they are selected does rot matter is  

P(E) = \frac{|E|}{|S|}

         = \frac{C(34, 6)}{C(40, 6)}\\\\= \frac{1344904}{3838380}\\\\=0.35

Therefore, the probability is 0.35

Check the attached files for additionals  

8 0
3 years ago
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