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3 years ago

12

What is 36/96 in simplest form

2 answers:

Tanzania [10]3 years ago

8 0

The answer is 3/8 :) Hope this helped!

sattari [20]3 years ago

6 0

36/96 in simplest form is 3/8

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Write an inequality that models the solution for 3x + 4.5 ≤ 5(x - 2)

lara [203]

Answer:

x ≤ 7.25

Step-by-step explanation:

1) $3x + 4.5$ ≤ $5(x - 2)$

<u>Distribute</u> <em>5</em> through the parenthesis.

2) $3x + 4.5$ ≤ $5x - 10$

Move the <u>variable</u> to the left side and change it's sign.

3) $3x + 4.5 - 5x$ ≤ $- 10$

Move the <u>constant</u> to the right side and change it's sign.

4) $3x - 5x$ ≤ $- 10- 4.5$

Subtract the <u>like terms</u>.

5) $-2x$ ≤ $-14.5$

Divide both sides of the inequality by <em>-2</em>.

6) $x$ ≤ $7.25$

3 0

3 years ago

7. Select each problem that has a quotient of 0.4*<br> 16 = 40<br> 24 = 6<br> 60 = 16<br> 3.6 - 9

mr Goodwill [35]

16=40 and then 60=16

8 0

3 years ago

What times what equals 14

viktelen [127]

2×7=14
14÷7=2
hope this helps

6 0

3 years ago

Read 2 more answers

Tracy has a cell phone plan that provides 250 free minutes each month for a flat rate of 29$. For any minutes over 250 tracy us

iVinArrow [24]

Answer:

Since Tracy is charged $29 for 250 free minutes so:

For x ≤ 250, f(x) = $29

tracy is charged an extra $0.35 per minute for calls over 250 minutes, so:

For x ≥ 250, f(x) = 29 + 0.35(x - 250)

7 0

3 years ago

A shoe manufacturer was investigating the weights of men's soccer cleats. He felt that the weight of these cleats was less than

aleksklad [387]

Answer:

The conclusion is that the researcher was correct

Step-by-step explanation:

From the question we are told that

The sample size is $n = 13$

The sample mean is $\= x = 9.63$

The standard deviation is $s = 0.585$

The significance level is $\alpha = 0.05$

The Null Hypothesis is $H_o : \mu = 0$

The Alternative Hypothesis is $H_a = \mu < 10$

The test statistic is mathematically represented as

$t = \frac{\= x - \mu }{\frac{s}{\sqrt{n} } }$

Substituting values

$t = \frac{9.63 - 10 }{\frac{0.585}{\sqrt{13} } }$

$t = - 2.280$

Now the critical value for $\alpha$ is

$t_{\alpha } = 1.645$

This obtained from the critical value table

So comparing the critical value of alpha and the test value we see that the test value is less than the critical value so the Null Hypothesis is rejected

The conclusion is that the researcher was correct

6 0

4 years ago