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ad-work [718]
3 years ago
12

Identify the vertex of the parabola with the quadratic equation u =6x squared - 72x + 220

Mathematics
1 answer:
BartSMP [9]3 years ago
3 0
Don't report what you don't understand

the x value of the vertex of the parabola in form
y=ax^2+bx+c
is -b/2a
given
y=6x^2-72x+220
x value of vertex is -(-72)/(2*6)=72/12=6
xvalue is 6
sub that for x in the equation

y=6(6)^2-72(6)+220
y=216-432+220
y=4

(x,y)
vertex is (6,4)
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