Identify the vertex of the parabola with the quadratic equation u =6x squared - 72x + 220

1 answer:

3 0

Don't report what you don't understand

the x value of the vertex of the parabola in form
y=ax^2+bx+c
is -b/2a
given
y=6x^2-72x+220
x value of vertex is -(-72)/(2*6)=72/12=6
xvalue is 6
sub that for x in the equation

y=6(6)^2-72(6)+220
y=216-432+220
y=4

(x,y)
vertex is (6,4)

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