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Tems11 [23]
3 years ago
7

Find the missing side of the triangle

Mathematics
1 answer:
kolezko [41]3 years ago
4 0

Answer:

2

Step-by-step explanation:

2

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Que número es 40% de 50?
uranmaximum [27]

Answer:

40

Step-by-step explanation:

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3 years ago
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Sarah completed about 85% of her school homework. Her friend Emily completed x percent homework more than Sarah. Which expressio
Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

85-x=100

85 represents sarah's hw

x represent Emily's hw

100 represents total completion

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3 years ago
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A fitted multiple regression equation is Y = 28 + 5X1 - 4X2 + 7X3 + 2X4. When X1 increases 2 units and X2 increases 2 units as w
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Answer:

A. Increase by 2

Step-by-step explanation:

Given that a  fitted multiple regression equation is

Y = 28 + 5X_1 -4X_2 + 7X_3 + 2X_4

This is a multiple regression line with dependent variable y and independent variables x1, x2, x3 and x4

The coefficients of independent variables represent the slope.

In other words the coefficients represent the rate of change of y when xi is changed by 1 unit.

Given that x3 and x4 remain unchanged and x1 increases by 2 and x2 by 2 units

Since slope of x1 is 5, we find for one unit change in x1 we can have 5 units change in y

i.e. for 2 units change in x1, we expect 10 units change in Y

Similarly for 2 units change in x2, we expect -2(4) units change in Y

Put together we have

10-8 =2 change in y

Since positive 2, there is an increase by 2

A. Increase by 2

5 0
3 years ago
WILL MARK BRAINIEST!!!
Zarrin [17]
R^2/2(pi/180*D-sin(D)) is the formula so 6^2/2(pi/180*120-sin(120)) is the problem which comes to about 22cm^2
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Question 31 pts Prove the statement is true using mathematical induction: 2n-1 ≤ n! Use the space below to write your answer. To
Sladkaya [172]

Answer:

P(3) is true since 2(3) - 1 = 5  < 3! = 6.  

Step-by-step explanation:

Let P(n) be the proposition that 2n-1 ≤ n!. for n ≥ 3

Basis: P(3) is true since 2(3) - 1 = 5  < 3! = 6.  

Inductive Step: Assume P(k) holds, i.e., 2k - 1 ≤ k! for an arbitrary integer k ≥ 3. To show that P(k + 1) holds:

2(k+1) - 1 = 2k + 2 - 1

≤ 2 + k! (by the inductive hypothesis)

= (k + 1)! Therefore,2n-1 ≤ n! holds, for every integer n ≥ 3.

4 0
3 years ago
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