Question

Jane was given a bag of sweets and ate two-thirds of them right away. The next day she ate two-thirds of the remainder and the following day she ate two-thirds of the remaining candy before stopping. Only 2 pieces of candy were left. How many sweets was he given in the beginning?

Answer 1

Answer:

54

Step-by-step explanation:

First you take two and multiply it by three, which gives you 6. Then you multiply it by three and get 18. Then you multiply and get 54.

Answer 2

Answer:

54

Step-by-step explanation:

Let the initial amount of sweets be x

Jane ate two-thirds of them = $\frac{2}{3}x$

Remaining sweets = $x-\frac{2}{3}x$

                               = $\frac{1}{3}x$

The next day she ate two-thirds of the remainder i.e. $\frac{2}{3} \times \frac{1}{3}x =\frac{2}{9}x$

Remaining sweets = $\frac{1}{3}x-\frac{2}{9}x$

                            = $\frac{1}{9}x$

The following day she ate two-thirds of the remaining candy before stopping.

She ate =  $\frac{2}{3} \times \frac{1}{9}x =\frac{2}{27}x$

Remaining sweets = $\frac{1}{9}x-\frac{2}{27}x=\frac{1}{27}x$

Now we are given that Only 2 pieces of candy were left

So, $\frac{1}{27}x=2$

$x=2 \times 27$

$x=54$

Hence she has given 54 sweets in the beginning.