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svetlana [45]
3 years ago
5

Jane was given a bag of sweets and ate two-thirds of them right away. The next day she ate two-thirds of the remainder and the f

ollowing day she ate two-thirds of the remaining candy before stopping. Only 2 pieces of candy were left. How many sweets was he given in the beginning?
Mathematics
2 answers:
Wewaii [24]3 years ago
6 0

Answer:

54

Step-by-step explanation:

First you take two and multiply it by three, which gives you 6. Then you multiply it by three and get 18. Then you multiply and get 54.

nevsk [136]3 years ago
6 0

Answer:

54

Step-by-step explanation:

Let the initial amount of sweets be x

Jane ate two-thirds of them = \frac{2}{3}x

Remaining sweets = x-\frac{2}{3}x

                               = \frac{1}{3}x

The next day she ate two-thirds of the remainder i.e. \frac{2}{3} \times \frac{1}{3}x =\frac{2}{9}x

Remaining sweets = \frac{1}{3}x-\frac{2}{9}x

                            = \frac{1}{9}x

The following day she ate two-thirds of the remaining candy before stopping.

She ate =  \frac{2}{3} \times \frac{1}{9}x =\frac{2}{27}x

Remaining sweets = \frac{1}{9}x-\frac{2}{27}x=\frac{1}{27}x

Now we are given that Only 2 pieces of candy were left

So, \frac{1}{27}x=2

x=2 \times 27

x=54

Hence she has given 54 sweets in the beginning.

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