Answer:
-0.555
Step-by-step explanation:
The terminal point of the vector in this problem is
(-2,-3)
So, it is in the 3rd quadrant.
We want to find the angle 
that gives the direction of this vector.
We can write the components of the vector along the x- and y- direction as:
The tangent of the angle will be equal to the ratio between the y-component and the x-component, so:
However, since we are in the 3rd quadrant, the actual angle is:
So now we can find the cosine of the angle, which will be negative:
To find points, we use the graphing technique or analytic algebra.
Answer: m∠CAD = 81°
Step-by-step explanation: <u>Diagonal</u> is a line that unites opposite sides.
ABCD is a prallelogram. One property of diagonal in a parallelogram is it separates the parallelogram in 2 congruent triangles.
The figure below shows ABCD with its diagonals.
Since diagonal divides a parallelogram in 2 congruent triangles, it means the internal angles are also congruent. So
m∠BAC = m∠CAD
4x + 5 = 5x - 14
x = 19
Then, m∠CAD is
m∠CAD = 5(19) - 14
m∠CAD = 81
The angle m∠CAD is 81°.
1. What is an equation of a line, in point-slope form, that passes through (1,-7) and has a slope of -2/3?
Point Slope form y − y1 = m(x − x1)
Y1: -7 x1:1 slope :-2/3
Y-(-7)=-2/3(x-1)
Y+7=-2/3(x-1)
2. What is the equation of a line, in point-slope form, that passes through (-2,-6) and had a slope of 1/3?
Y-(-6)=1/3(x-(-2))
Y+6=1/3(x+2)
3.What is an equation in point-slope form of the line that passes through the points (4,5) and (-3,-1)
SlopeM: =change in y/change in x
M= -1-5/-3-4
M= -6/-7
M=6/7
So now slope:6/7, point (4,5)
Y-y1=m(x-x1)
Equation in point slope
Y-5=6/7(x-4)
Treat it just like and equation at first. Multiply the 10 on both sides to get rid of it, leaving you with 50 
x. Then on the number line, since there is a line under it, you would make a filled in circle and an arrow pointing towards 51 and beyond
