what is the probability of randomly choosing a penny and a nickel from a cup of coins that contains a penny nickel a dime and a
quarter
1 answer:
There are 4 coins in the cup.
Prob( choosing first a penny then a nickel) = 1/4 * 1/3 = 1/12
Prob(choosing first a nickel then a penny) = 1/4 * 1/3 = 1/12
Required probability =1/12 + 1/12 = 1/6 Answer
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Answer:
Step-by-step explanation:
Subtract the x terms:
Add 5 to both sides:
Multiply both sides by -1 and flip the inequality symbol:
Divide both sides by 5:
A= -2 I hope this was correct and if it helped,... Thank you! ^_^
Hello ;)
244÷5= 48,8
So the result is: $48,8
Answer:
I believe the answer is C, x+1 :)
H(x) = 16 - x
plug -4 in as x
H(x) = 16 - (-4)
solve 16 - (-4)
H(x) = 20
your answer is A)20
