Y+2=2(X-0) OR Y-6=2(X-4). Either one works.
Assume the graph is drawn with m as the x-axis, and s as the y-axis. If it is drawn the other way, it would be just a reflection about the x=y line.
There are two unspecified but implicit conditions, namelym>=0 and s>=0, which correspond to the m- and s-axes (horiz. & vert.) when equality holds in either case.
s+m<100 is a solid line at 45 degrees intersecting the m- and s-axes at (0,100), and (100,0) respectively.
s+2m>100 is a solid line with slope -2 intersecting the axes at (0,50) and (100,0).
The feasible region (shaded) is between the two lines, but above the horizontal axis.
If the graph is drawn the other way, the feasible region is between the two lines, and to the right of the vertical axis.
