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Bezzdna [24]
3 years ago
13

Zene deposited $50 in a savings account earning 5% interest, compounded annually. To thenearest cent, how much will he have in 3

years?
Mathematics
1 answer:
JulsSmile [24]3 years ago
6 0

Answer:

\$57.88  

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=3\ years\\ P=\$50\\ r=5\%=5/100=0.05\\n=1  

substitute in the formula above

A=50(1+\frac{0.05}{1})^{1*3}  

A=50(1.05)^{3}  

A=\$57.88  

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If f(x) = -(1/x^3) and x takes on successive values from -10 to 0.1 ,
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Alright, this one is a little interesting... Let's perform some tests to figure out what is happening:
f(-10) = -(1/(-10)^3) = -(1/-1000) = 1/1000  (positive)
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f(-1) = -(1/(-1)^3) = -(1/-1) = 1 (positive, bigger than the last one)
f(-0.1) = -(1/(-0.1)^3) = -(1/-0.001) = 1/0.001 = 1000 (positive, bigger than the last one)
f(0) = -(1/0^3) = undefined!
f(0.1) = -(1/(0.1)^3) = -(1/0.001) = -1/0.001 = -1000 (negative)
f(1) = -(1/1^3) = -(1/1) = -1 (negative, but bigger than last one)

It's a little confusing with the undefined part at x = 0. What I can say is this, it is increasing from -10 up to 0, something weird happens at 0 and it resets, and starts increasing from 0 up to 0.1. 

I guess A would be the best answer?

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Step-by-step explanation:

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