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pantera1 [17]
3 years ago
6

A teacher says that the top 14​% of the class received an A on the last test. The scores were normally distributed with mean 70

and standard deviation 12. Find the minimum score required to get an A.
Mathematics
1 answer:
aleksandrvk [35]3 years ago
4 0

Answer: The minimum score would be 83.08.

Step-by-step explanation:

Since we have given that

Mean = 70

Standard deviation = 12

Top 14%  of the class received an A on last test.

So, right tail of (100-14=86%) = 1.09

So, the minimum score required to get an A is given by

x=z\times s+\mu\\\\x=1.09\times 12+70\\\\x=13.08+70\\\\x=83.08

Hence, the minimum score would be 83.08.

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5x– 4y = -10<br> y = 2x – 5<br> y =<br> x =
Kitty [74]

Answer:

see the attached picture please

4 0
3 years ago
find the smallest number of terms of the AP "-54,-52.5,-51,-49.5" ....that must be taken for the sum of the terms to be positive
wel

The smallest number of terms of the AP that will make the sum of terms positive is 73.

Since we need to know the number for the sum of terms, we find the sum of terms of the AP

<h3>Sum of terms of an AP</h3>

The sum of terms of an AP is given by S = n/2[2a + (n - 1)d] where

  • n = number of terms,
  • a = first term and
  • d = common difference

Since we have the AP "-54,-52.5,-51,-49.5" ....", the first term, a = -54 and the second term, a₂ = -52.5.

The common difference, d = a₂ - a

= -52.5 - (-54)

= -52.5 + 54

= 1.5

<h3>Number of terms for the Sum of terms to be positive</h3>

Since we require the sum of terms , S to be positive for a given number of terms, n.

So, S ≥ 0

n/2[2a + (n - 1)d] ≥ 0

So, substituting the values of the variables into the equation, we have

n/2[2(-54) + (n - 1) × 1.5] ≥ 0

n/2[-108 + 1.5n - 1.5] ≥ 0

n/2[1.5n - 109.5] ≥ 0

n[1.5n - 109.5] ≥ 0

So, n ≥ 0 or 1.5n - 109.5 ≥ 0

n ≥ 0 or 1.5n ≥ 109.5

n ≥ 0 or n ≥ 109.5/1.5

n ≥ 0 or n ≥ 73

Since n > 0, the minimum value of n is 73.

So, the smallest number of terms of the AP that will make the sum of terms positive is 73.

Learn more about sum of terms of an AP here:

brainly.com/question/24579279

#SPJ1

4 0
2 years ago
What is the probability that a point chosen at random in the given figure will be inside the smaller square?
Aliun [14]
I have to interpret that:

1) the smaller square has side length = 3 cm

2) the bigger square has side length = 5 cm

3) the smaller square is completely inside the bigger square.

4) the points cannot be outside the bigger square



Under those assumptions the probability that a point is inside the smaller square  is

P (inside the smaller square) = area of the smaller square / area of the bigger square

P (inside the smaller squere) = (3cm)^2 / (5cm)^2 =  9 / 25


Answer: 9 / 25
8 0
3 years ago
Factorize: (a+b)^2 + 4 (a+b)+ 4
pashok25 [27]
Factorized: (a + b + 2) ^2
3 0
3 years ago
A 6 sided die was rolled 9 times. What is the mode of these rolls?
yuradex [85]
That 1,2,3,4,5,6 is one the die and it has a chance to at least get all the numbers at least once but u dont have enough data so i can help u more.
6 0
2 years ago
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