A teacher says that the top 14% of the class received an A on the last test. The scores were normally distributed with mean 70
1 answer:
Answer: The minimum score would be 83.08.
Step-by-step explanation:
Since we have given that
Mean = 70
Standard deviation = 12
Top 14% of the class received an A on last test.
So, right tail of (100-14=86%) = 1.09
So, the minimum score required to get an A is given by
Hence, the minimum score would be 83.08.
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Consider the polynomial .
For this polynomial to be trinomial with a degree of 3. We have to identify the missing exponent of the 'y' term.
Let the missing exponent of the 'y' term be 0
So, the polynomial will be
=
= which is not a trinomial, which is a binomial.
So, the missing exponent of 'y' can'not be zero.
Let the missing exponent of the 'y' term be 2
So, the polynomial will be
=
= which is a trinomial of degree 4.
So, the missing exponent of 'y' can'not be '2'.
If we will take the missing exponent of 'y' more than 2, than the degree of the given polynomial will not be 3 anymore.
Let the missing exponent of the 'y' term be 1
So, the polynomial will be
=
= which is a trinomial of degree 3
So, the missing exponent of 'y' is 1.
Answer:
456
Step-by-step explanation:
Let X be the SATscore scored by the students
Given that X is normal (1000,200)
By converting into standard normal variate we can say that
is N(0,1)
To find the top 10% we consider the 90th percentile for z score
Z 90th percentile = 1.28
i.e. only students who scored 456 or above only should be considered.