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Bess [88]
3 years ago
5

its SAT day ! Any final tips or formulas i should remember? Mostly for math its my weakest subject and I only need 60 more pts t

o qualify for my min at my dream college.
Mathematics
1 answer:
timama [110]3 years ago
5 0
Review your notes and have a friend test you on them. Go over anything you had trouble on by reading it 10 times, writing it 10 times, and saying it out loud 2 times. It should help you remember and good luck! :)
You might be interested in
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
tom put 18 gallons of mid grade gas in his truck and filled up his empty five gallon gas can with regular gas for his lawnmower
k0ka [10]

Answer:

Step-by-step explanation:

Let price of milgrade gas be x and price of lawnmower gas be y.

18x + 5y=59.51

14x+y=39.75

Isolate one variable and substitute to solve for other variable.

8 0
3 years ago
A car traveled 88 km in 1 hour, 90 km in the next 2 hours, and then 76 km in 1 hour before reaching its destination. what was th
luda_lava [24]

The formula for Average speed = \frac{Total Distance}{Total Time}

The car travels 80 km in 1 hour.

Then the car travels 90 km in 2 hours.

And finally the car travels 76 km in 1 hour

So the total distance covered by the car = 80 + 90 + 76 = 246 km

The total time taken to cover this distance = 1 + 2 + 1 = 4 hours.

So average speed = \frac{246}{4}= 61.5

The average speed of the car is 61.5 km / h

3 0
3 years ago
Which of the following will you construct in this lesson?
Vikentia [17]

Answer:

The question is not complete or you forgot to attatch the image. Repost your question

8 0
2 years ago
An empty cubical carton is side 7cm. Can you fill 1000 cubes of side 1cm in it ?
Shalnov [3]
An empty cubical carton of side 7cm has the volume:
7 x 7 x 7 = 343cm³

A cube of side 1cm has the volume:
1 x 1 x 1 = 1cm³

From this, we can see that a 1000 cubes of side 1cm has the volume:
1000 x 1cm³ = 1000cm³

But we know that the cubical carton of side 7cm only has a volume of 343cm³.

Since 1000cm³ > 343cm³,
you cant fill 1000 cubes of side 1cm in such a carton.

TL;DR
No

Hope this helps
8 0
2 years ago
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