Answer:
Step-by-step explanation:
Let |x-a|=b
then x-a=±b
so x-a=b
or x=a+b
so a+b=18 ...(1)
and x-a=-b
or x=a-b
or a-b=8 ...(2)
adding (1) and (2)
2a=26
a=26/2=13
subtract (2) from (1)
2b=10
b=10/2=5
|x-13|=5
Answer:
ZP=66
Step-by-step explanation:
Quadrilateral WXYZ is a rectangle. Diagonals WY and ZX intersect at P. If PY=3x−5 and WP=2x+11, find the value of ZP.
To solve each of the problems, I first looked for the equation that had the same slope value and then plugged in the 'x' coordinate to see if it gave me the correct 'y' coordinate.
1.)
D.) y = 5x + 4
14 = 5(2) + 4
14 = 10 + 4
14 = 13
2.)
C.) y = 1/5x - 19
-16 = 1/5 (15) - 19
-16 = (3) - 19
-16 = -16
3.) First, get 'y' by itself by subtracting 4x from both sides and dividing the whole equation by -12. To find perpendicular lines, the slope must be the opposite reciprocal of the first slope (in this case, flip the fraction to get the three on top). Add the opposite sign to the slope as your final step.
4x - 12y = 2
-4x -4x
-12y = -4x + 2
-12y / -12 = -4x / -12+ 2 / -12
y = 1/3x - 1/6
C.) y = -3x + 29
-1 = -3(10) + 29
-1 = (-30) + 29
- 1 = -1
Answer:idk sorry
Step-by-step explanation:
Step-by-step explanation:
only attached the displacement/time graph
