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3 years ago

If i is raised to an odd power, then it can not simplify to be

2 answers:

6 0

A real number

ok so
any even power is i^(2n) where n is a whole number
if n=1
i^2=(√-1)^2=-1

if i^3, then it is equal to (i^2)(i)=(-1)(i)=-i
if i^4, then it is equal to (i^2)(i^2)=(-1)(-1)=1

therefor
i^1=i
i^2=-1
i^3=-i
i^4=1
then it repeats

look at the odd powers
i and -i
they are complex

therefor

if i is raised to an odd power, it cannot be simplified to be a real number

oksano4ka [1.4K]3 years ago

3 0

Answer:

-1

Step-by-step explanation:

If i is raised to an odd power, then it can not simplify to be

-1

-i

Odyssey

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Step-by-step explanation:

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4 years ago

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Answer:

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3 years ago

This table shows the number of points two teams scored in five games

mezya [45]

Answer:

2.16

Step-by-step explanation:

The question is on mean absolute deviation

The general formula ,

Mean deviation = sum║x-μ║/N where x is the each individual value, μ is the mean and N is number of values

Team 1

Finding the mean ;

$mean= \frac{51+47+35+48+64}{5} =49$

Points Absolute Deviation from mean

51 2

47 2

35 14

48 1

64 15

Sum 34

Absolute mean deviation = 34/5= 6.8

Team 2

Finding the mean

$mean=\frac{27+55+53+38+41}{5} = 42.8$

Points Absolute deviation from the mean

27 15.8

55 12.2

53 10.2

38 4.8

41 1.8

Sum 44.8

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Solution

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4 years ago

Which of the following are equivalent to -7?

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3 years ago

In the data set below, what is the interquartile range? 7 1 5 5 9 Submit

Marizza181 [45]

Answer:

Step-by-step explanation:

The interquartile range is the difference between the upper quartile and the lower quartile.

First find the median.

The median is the middle value of the data set arranged in ascending order

1 5 5 7 9 ← data in ascending order

↑ median

The lower quartile is the middle value of the data to the left of the median. If there is not an exact middle then it the average of the values on either side of the middle.

1 5

↑ lower quartile = $\frac{1+5}{2}$ = 3

The upper quartile is the middle value of the data to the right of the median.

7 9

↑ upper quartile = $\frac{7+9}{2}$ = 8

Thus

interquartile range = 8 - 3 = 5

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3 years ago