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seraphim [82]
3 years ago
7

If i is raised to an odd power, then it can not simplify to be

Mathematics
2 answers:
Tomtit [17]3 years ago
6 0
A real number

ok so
any even power is i^(2n) where n is a whole number
if n=1
i^2=(√-1)^2=-1

if i^3, then it is equal to (i^2)(i)=(-1)(i)=-i
if i^4, then it is equal to (i^2)(i^2)=(-1)(-1)=1

therefor
i^1=i
i^2=-1
i^3=-i
i^4=1
then it repeats

look at the odd powers
i and -i
they are complex

therefor

if i is raised to an odd power, it cannot be simplified to be a real number
oksano4ka [1.4K]3 years ago
3 0

Answer:

-1

Step-by-step explanation:

If i is raised to an odd power, then it can not simplify to be

<u><em>-1</em></u>

-i

i

Odyssey

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Mrrafil [7]

Remark

So CAB is a base 16 number? I hope that's correct. I'll treat it that way. If I am incorrect, please leave a note and I'll modify my answer accordingly.

Expand

A = 10 in decimal

B = 11  in decimal

C = 12 in decimal

B is the "units" value in decimal it is 11

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Answer

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Answer:

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Step-by-step explanation:

-15/9+9/4

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