Answer:
the numerical value of the correlation between percent of classes attended and grade index is r = 0.4
Step-by-step explanation:
Given the data in the question;
we know that;
the coefficient of determination is r²
while the correlation coefficient is defined as r = √(r²)
The coefficient of determination tells us the percentage of the variation in y by the corresponding variation in x.
Now, given that class attendance explained 16% of the variation in grade index among the students.
so
coefficient of determination is r² = 16%
The correlation coefficient between percent of classes attended and grade index will be;
r = √(r²)
r = √( 16% )
r = √( 0.16 )
r = 0.4
Therefore, the numerical value of the correlation between percent of classes attended and grade index is r = 0.4
He would be 15 years old depending on his birthday if he has a late birthday he would be 14 years and if he had a early birthday he would be 16 years old
51/4 because you multiply 12*4 which is 48 and add 3 so you get 51. You keep the denominator so you should get 51/4.
Answer:
No Solution
Step-by-step explanation:
<u>-1/7</u>(14+28p)-13=<u>4</u>(1/2p-3)-6p
-2-4p-13=2p-12-6p
rearrange the question so like terms are next to each other
<u>-2-13</u>-4p=<u>2p-6p</u>-12
-15-4p=-4p-12
add 12 to both sides
-3-4p=-4p
add 4p to both sides
-3=0
No solution
Step-by-step explanation:
60-4 = 56
56 divided by 2.8 = 20 miles
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